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VARVARA [1.3K]
3 years ago
9

Explain how you can tell the frequency of a data value by looking at a dot plot

Mathematics
1 answer:
balandron [24]3 years ago
6 0
Dot plot is to see how many people voted for that object or something
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Which quadrilaterals are considered parallelogram
Elenna [48]

Answer: Rectangle, Rhombus, Square

Step-by-step explanation:

6 0
3 years ago
the sum of two consecutive integers is -49 write an equation that models this situation and find the values of the two integers
hodyreva [135]
Х is the first <span>integer
</span>(x+1) is the second integer

x + x + 1 = -49
2x + 1 = - 49
2x = -49 - 1
2x = -50
x = -25  first integer
-25 + 1 = -24 second integer

Answer: -25 and -24
7 0
3 years ago
Read 2 more answers
Simplify the expression. 25^1/2 + 81^1/4
Vanyuwa [196]

Answer:

32.75

Step-by-step explanation:

4 0
3 years ago
A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the
Naya [18.7K]

Answer:

The area is growing at a rate of \frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 \frac{cm}{min} and we identify such as the following differential rate:

\frac{dr}{dt} = 3\,\frac{cm}{min}

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find  \frac{dA}{dt}.

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

A=\pi\,r^2

We now apply the derivative operator with respect to time (\frac{d}{dt}) to this equation, and use chain rule as we find the quadratic form of the radius:

\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}

Now we replace the known values of the rate at which the radius is growing ( \frac{dr}{dt} = 3\,\frac{cm}{min}), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\

which we can round to one decimal place as:

\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

4 0
3 years ago
The angle θ1\theta_1 θ 1 ​ theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end
melomori [17]

Answer:

\dfrac{3\sqrt{13}}{11}

Step-by-step explanation:

Given that the angle \theta_1  is located in Quadrant II; and

\cos(\theta_1)=-\dfrac{2}{11}

In Quadrant II, x is negative and y is positive.

\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\

To find \sin(\theta_1), we first determine the opposite angle of \theta_1.

This will be done using the Pythagoras theorem.

Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}

Therefore:

\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}

6 0
3 years ago
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