Name all numbers between 67 and 113 that are a multiple of 4, 9 and 12.

2 answers:

8 0

Hello!

I believe that there are 2 number that are in between the given numbers and are multiples of 4, 9, and 12. The numbers are...
72 and 108.

You can find these numbers by counting by the given one digit numbers
For example...

9, 18, 27, 36, 45, 54, 63, 72
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30..., 68, 70, 72

You can do the same for 108 as well

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72..., 104, 108
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30..., 100, 102, 104, 106, 108

I hope this helps!

Sophie [7]3 years ago

5 0

There are only 2 possbile answers: <span>72 and 108.</span>

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The table shows some values of f(x) and g(x) for different values of x: x f(x) = 15x − 12 g(x) = 3x −2 0.11 −1 −27 0.33 0 −12 1

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3 years ago

Please help me. I'm stupid.

Gwar [14]

Answer:

$\displaystyle 36\:units$

Step-by-step explanation:

Split up this Isosceles, Right Triangle into two congruent smaller right triangles. The reflexive side [the line that splits them apart] is 6 units, and both legs are 8 units, leaving the hypotenuses to AUTOMATICALLY be 10 units, according to the Pythagorean Theorem:

$\displaystyle a^2 + b^2 = c^2 \\ \\ 6^2 + 8^2 = 10^2 \\ \\ 36 + 64 = 100 \\ \\ 100 = 100$

With this Pythagorean Triple, we know that our dimensions are correct. Now, to find the perimeter, just add up all the sides EXCEPT for the divider:

$\displaystyle 2[10] + 2[8] = 20 + 16 = 36$

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