Name all numbers between 67 and 113 that are a multiple of 4, 9 and 12.

2 answers:

8 0

Hello!

I believe that there are 2 number that are in between the given numbers and are multiples of 4, 9, and 12. The numbers are...
72 and 108.

You can find these numbers by counting by the given one digit numbers
For example...

9, 18, 27, 36, 45, 54, 63, 72
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30..., 68, 70, 72

You can do the same for 108 as well

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72..., 104, 108
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30..., 100, 102, 104, 106, 108

I hope this helps!

Sophie [7]3 years ago

5 0

There are only 2 possbile answers: <span>72 and 108.</span>

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Solve for j. 144j2 + 21 = 85

Sphinxa [80]

Answer:

2/3

Step-by-step explanation:

I assume the 2 after the j is a square. So, we bring the 21 to the other side by subtracting it from both sides, getting 144j^2=64. Now we divide to get 64/144 = j^2. Make sure NOT to simplify it, it's perfect right now. The square root of that is $\sqrt{64}/ \sqrt{144}$ , or 8/12, which we can now simplify to 2/3. Hope this helps!