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Salsk061 [2.6K]
3 years ago
15

Help meeeeeeeeeeeeeee​

Mathematics
2 answers:
sergejj [24]3 years ago
7 0

Hey There!!

Your best choice is 1.

Because, We have to find a function where f(2)=4. It means the value of function is 4 at x=2.

In graph 1, the value of function is 4 at x=2, therefore option 1 is correct.

In graph 2, the value of function is -4 at x=2, therefore option 2 is incorrect.

In graph 3, the value of function is not shown in the graph at x=2, therefore option 3 is incorrect.

In graph 4, the value of function is not shown in the graph at x=2, therefore option 4 is incorrect.

Thus, correct option is 1.

Hope This Helps!!

AveGali [126]3 years ago
5 0

Answer:

Step-by-step explanation:

I believe the correct answer from the choices listed above would be the first option. The graph that shows a function where f(2) = 4 would be the graph that passes through point (2,4) which is shown in the first graph. Hope this answers the question.

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Suzi tiene $20 dólares en una cuenta de ahorros. El tipo de intereses es del 10% anual. Cuanto ganara en un año
Damm [24]

Responder:

$ 22

Explicación paso a paso:

Monto principal = $ 20

Tasa de interés = 10% = 10/100 = 0.1

Tiempo = 1 año

Cantidad ganada después de 1 año:

Principal (1 + (tasa de interés * tiempo))

$ 20 (1 + (0,1 * 1))

$ 20 (1 + 0.1)

$ 20 (1,1)

$ 22

Ganará $ 22 después de un año.

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Answer:

0.04

Step-by-step explanation:

Looking at the chart we can see that there are 0, 1, 2 and 3 defective parts in one column while the other column says the probability of each happening. Look at the probability of there being 2 defective parts and that will be your answer.

4 0
3 years ago
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just olya [345]

Answer:

m=20

Step-by-step explanation:

hope this helps!! :)

8 0
3 years ago
You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%
bezimeni [28]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}

\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}

6 0
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Step-by-step explanation:

THE ANSWER IS C. 31 INCHES

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