(-2, -4), (2, 4) what is this in slope intercept form?
1 answer:
You might be interested in
let's recall that the domain of a set is always the list of all x-coordinates in each pair.
The parabola is y² = 6x
This defines a parabola with its vertex at the origin (0,0).
When the equation is compared with y² = 4ax, then
4a = 6
a = 3/2
Therefore the focus is at
(a, 0) = (3/2, 0)
The directrix is located at
(-a, 0) = (-3/2, 0)
The parabola opens right because a > 0.
Answer:
The directrix is x = - 3/2.
The parabola opens right.
This defines a parabola with its vertex at the origin (0,0).
When the equation is compared with y² = 4ax, then
4a = 6
a = 3/2
Therefore the focus is at
(a, 0) = (3/2, 0)
The directrix is located at
(-a, 0) = (-3/2, 0)
The parabola opens right because a > 0.
Answer:
The directrix is x = - 3/2.
The parabola opens right.