If the order does not matter, cars can be arranged in 20 ways
If an order is important, cars can be arranged in 120 ways
The probability that the three newest cars end up parked in the driveway is 0.167
1. If the order does not matter, combination is used

Here, n=6 r=3
using formula,we get

2. If an order is important, Permutation will be applicable

∴
3. the probability that the three newest cars end up parked in the driveway
P=
=
=
=
≈ 0.167
Hence, If the order does not matter, cars can be arranged in 20 ways
If an order is important, cars can be arranged in 120 ways
The probability that the three newest cars end up parked in the driveway is 0.167
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Here is the formula that your going to need to use A=P(1+r/n)^nt
So P=500, R=0.082, N=1, T=15
Plug it into your equation and you have A=500(1+0.082/1)^(1)(15)
Simplify what's in the parenthesis A=500(1.082)^(1)(15)
Multiply your exponents A=500(1.082)^15 Then A=500(3.26)
Finally you multiply your last two numbers to get A=1,630
So after 15 years you would have $1,630
I hope this helped you :)
Answer:
the answer is option (D)3*3
Answer:
y=97/100x + 7/10
Step-by-step explanation: