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Hunter-Best [27]
3 years ago
8

Point slope form. (-5,-1) and (6,-5)

Mathematics
1 answer:
TEA [102]3 years ago
6 0

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - point on a line</em>

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (-5, -1) and (6, -5). Substitute:

m=\dfrac{-5-(-1)}{6-(-5)}=\dfrac{-5+1}{6+5}=-\dfrac{4}{11}

Put the value of a slope and coordinates of a point to the equation of a line:

(-5,\ -1),\ m=-\dfrac{4}{11}\\\\y-(-1)=-\dfrac{4}{11}(x-(-5))\\\\y+1=-\dfrac{4}{11}(x+5)

(6,\ -5),\ m=-\dfrac{4}{11}\\\\y-(-5)=-\dfrac{4}{11}(x-6)\\\\y+5=-\dfrac{4}{11}(x-6)

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