Point slope form. (-5,-1) and (6,-5)

Mathematics

1 answer:

TEA [102]3 years ago

6 0

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have two points (-5, -1) and (6, -5). Substitute:

$m=\dfrac{-5-(-1)}{6-(-5)}=\dfrac{-5+1}{6+5}=-\dfrac{4}{11}$

Put the value of a slope and coordinates of a point to the equation of a line:

$(-5,\ -1),\ m=-\dfrac{4}{11}\\\\y-(-1)=-\dfrac{4}{11}(x-(-5))\\\\y+1=-\dfrac{4}{11}(x+5)$

$(6,\ -5),\ m=-\dfrac{4}{11}\\\\y-(-5)=-\dfrac{4}{11}(x-6)\\\\y+5=-\dfrac{4}{11}(x-6)$

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