All categories

3 years ago

What is the Kinetic energy of a 2000 kg bus that is moving at 30m/s? Explain please

Mathematics

1 answer:

agasfer [191]3 years ago

4 0

There's a formula for that.

KE = (1/2)mv²

... = (1/2)(2000 kg)(30 m/s)²

... = 900,000 kg·m²/s²

... = 900,000 J

_____

It is helpful to know the relationship between kilograms, meters, seconds, and Newtons or Joules.

1 J = 1 kg·m²/s²

You might be interested in

You have a new puppy that is one fifth of the size of your older dog.if your older dog wieghts 25 2/5 pounds how much does your

ELEN [110]

Answer is 25.4*0.2= 5.08

5 0

2 years ago

Solve the following formula for b<br><br> y=6(5a+3b)<br> what does b equal

Ratling [72]

Answer:

30a + 18b

Step-by-step explanation:

6(5a+3b)

Just multiply the six in both numbers

( 6x5a) + (6x3b)

= 30a +18b

Hope this helps =)

4 0

2 years ago

Neil has 3 partially full cans of white paint . They contain 1/3 gallon , 1/5 gallon and 1/2 gallon of paint. About how many pai

stepan [7]

Answer:

About 1 gallon. (32/30)

Step-by-step explanation:

First get a LCM (least common multiple) for 3, 5, and 2.

Now we have 30. Make 30 the denominator for all.

10/30

15/30

7/30

Then add them all up to get 32/30.

About 1 gallon.

4 0

3 years ago

Read 2 more answers

Simplify the Square root of 72a6b3c2

Korolek [52]

The problem simplified is 36√ 2abc

5 0

2 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

2 years ago