Answer: Find the negative reciprocal of the slope of the original line and use the slope-intercept form y=mx+b to find the line perpendicular to y=1/5x−1. y=−5x−17
Can someone help me find x please
1 answer:
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Ninety-five hundreths is equivalent to 
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The numerator and denominator have a basic factor of 5, so we can divide the numerator and denominator by 5.
The numerator and denominator have a basic factor of 5, so we can divide the numerator and denominator by 5.
*see attachment for the missing figure
Answer:
Angle ADE = 45°
Angle DAE = 30°
Angle DEA = 105°
Step-by-step explanation:
Since lines AD and BC are parallel, therefore:
Given that angle Angle CBE = 45°,
Angle ADE = Angle CBE (alternate interior angles are congruent)
Angle ADE = 45° (Substitution)
Angle DAE = Angle ACB (Alternate Interior Angles are congruent)
Angle ACB = 180 - 150 (angles on a straight line theorem)
Angle ACB = 30°
Since angle DAE = angle ACB, therefore:
Angle DAE = 30°
Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)
Angle DEA = 180 - (45 + 30) (Substitution)
Angle DEA = 180 - 75
Angle DEA = 105°
