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olga2289 [7]
3 years ago
11

For which triangle does the equation 4^2+4^2 =c^2 apply?

Geography
1 answer:
Dahasolnce [82]3 years ago
5 0

Answer:

A Right triangle

Explanation:

A^2+B^2=C^2

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Which gulf is off the southern coast of the united states?
Brums [2.3K]
<h2>Answer: The Gulf of Mexico </h2>

The Gulf of Mexico is an ocean basin that formed after the collision of the continental plates and the sinking of the seabed during the rupture of the former Pangea mega continent millions of years ago.

This gulf is also the ninth largest water surface in the world, which is contained among the littorals of Mexico, the United States and the island of Cuba. Therefore, this mass of water corresponds to the Atlantic Ocean in the northern part of the American Continent.

4 0
3 years ago
a rural kansas watershed that is ungauged has an area of 475 acres and a main channel length of 6870 feet with an average slope
dlinn [17]

Answer:

\mathbf{Q_p  =682 \ \  ft^3/s}

Explanation:

Given that:

Area = 475 acres

The length of the channel (L) = 6870 feet

The average water shield slope (S) = 100 feet/mile

Since; 1 mile = 5280 feet

Burst duration D = 15 min

∴

100 feet/mile = 100/5280

The average water shield slope (S) = 5/264

Using hydrograph method:

The time of concentration t_c = 0.0078L^{0.77} S^{-0.385}

where;

L = 6870

S = 5/264

t_c = 0.0078(6870)^{0.77} (\dfrac{5}{264})^{-0.385}

t_c =32.34 min

Since 60 min = 1 hour

32.34 min will be (32.34*1)/60

= 0.539 hour

Lag time T_l = 0.67\times t_c

T_l = 0.67\times 32.34

T_l = 21.6678\ min

The time to peak i.e

T_p = \dfrac{D}{2}+ T_L \\ \\  T_p = \dfrac{15}{2}+ 21.6678 \\ \\  T_p = 29.168 \ min

T_r = \dfrac{T_p}{5.5} \\ \\  T_r = \dfrac{29.1678}{5.5} \\ \\ T_r = 5.30 \ min

Since D = 15 min is not equal to T_r, then we hydrograph apart from T_r duration lag time.

Then;

T_p \ ' = T_p + \dfrac{D-t_r}{4} \\ \\ T_p \ ' = 29.168 + \dfrac{15-5.30}{4} \\ \\ T_p \ ' = 31.593

Now, we need to determine the peak discharge Q_p by using the formula:

Q_p  = \dfrac{484 \times A}{T_p \ '}

where

484 = peak factor

Recall that A = 475 acres, to miles, we have:

A = 0.7422 mile²

T_p \ ' = 31.593/60

∴

Q_p  = \dfrac{484 \times 0.7422}{\dfrac{31.593}{60}}

\mathbf{Q_p  =682 \ \  ft^3/s}

7 0
3 years ago
Which is an example of relative location
grigory [225]

Answer:

the Empire State Building is 365 kilometres

Explanation:

a description of how a place is related to other places.

8 0
2 years ago
How long would it take a typical jet to travel to the Sun from Earth?
vodomira [7]

Answer: It would take you about 19 years to reach the Sun.

Explanation: Sun is about 8.3 light minutes from the Earth. This means it would take 8.3 minutes for light to reach from the Surface of the Sun to reach the Earth. If you are traveling in a Jumbo Jet , it would take you about 19 years to reach the Sun

6 0
3 years ago
What do you understand by gm crops? agriculture
Artemon [7]
Not sure sorry ab that I need points
3 0
3 years ago
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