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3 years ago

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Multiply the polynomials. (5x2 + 2x + 8)(7x – 6) A. 35x3 – 16x2 – 44x – 48 B. 35x3 – 14x2 + 44x – 48 C. 35x3 – 16x2 + 44x + 48 D

. 35x3 – 16x2 + 44x – 48

1 answer:

ZanzabumX [31]3 years ago

5 0

Answer:

D) 35x³ - 16x² + 44x - 48

Step-by-step explanation:

(5x2 + 2x + 8)(7x – 6) = (5x2 + 2x + 8)* 7x + (5x2 + 2x + 8)*(– 6)

= (5x2*7x + 2x*7x + 8*7x) + (5x2*(-6) + 2x*(-6) + 8*(-6) )

=35x³ + 14x² + 56x - 30x² - 12x - 48

= 35x³ - 16x² + 44x - 48

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Substituting the values of

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Can someone please tell me the answer on this.

marishachu [46]

Answer: x = 31

Step-By-Step:

<u>To Find x:</u>

<u /> $\left(2x+20\right)+\left(x+10\right)+\left(2x-5\right)=180$ (Angle Sum Property Of Triangles)

(Remove the brackets)

<u /> $2x+20+x+10+2x-5=18$ <u />

(Group Accordingly)

<u /> $2x+x+2x+20+10-5=180$ <u />

= $5x+20+10-5=180$

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A line has a slope of − 1 and a y-intercept of 7. What is the equation of the line in standard form?

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2 years ago

Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Dahasolnce [82]

<em>Note: you may have unintentionally missed to add the complete question. Therefore, after a little research, I am able to find the complete question which I am attaching to solve your query, which anyways would clear your concept. </em>

The complete Question:

Keenan gives Tisha half of his strawberries. Tisha keeps 4 of the strawberries she got from Keenan and gives the rest to Suvi.

a) Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.

b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Answer:

Part a)

An expression for the number of strawberries Tisha gives to Suvi will be:<em> </em> $n=\frac{k}{2} -4$

Part b)

Keenan could not have started with 6 strawberries

Step-by-step explanation:

Part a) <em>Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.</em>

Let $k$ be the total number of strawberries which Keenan has.

So,

$\frac{k}{2}$ is the number of strawberries Keenan gave to Tisha.

As Tisha keeps 4 strawberries and gives the rest to Suvi. Let $n$ be the number of strawberries which Suvi has.

So,

$n=\frac{k}{2} -4$

$\frac{k}{2}=n+4$

$k=2n+8$

Therefore, an expression for the number of strawberries Tisha gives to Suvi will be:<em> </em> $n=\frac{k}{2} -4$

b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Considering the expression for the number of strawberries Tisha gives to Suvi

$n=\frac{k}{2} -4$

Putting $k = 6$ in the expression

$n=\frac{6}{2} -4$

Solving the expression

$n=3-4$ ∵ $\mathrm{Divide\:the\:numbers:}\:\frac{6}{2}=3$

$\mathrm{Subtract\:the\:numbers:}\:3-4=-1$

$n=-1$

So, Keenan would have started with 6 strawberries, then Suvi would have -1 strawberries. Since, strawberries cannot be negative as Suvi cannot have negative number of strawberries.

Therefore, Keenan could not have started with 6 strawberries.

Keywords: word problem, expression

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