Question

2. An 82 kg man on a diving board drops from rest 3.0 m above the surface of the water

Answer 1

Yo sup??

mass of man=82 kg

mgh=1/2mv^2

v^2=2gh

=2*10*3

=60

v=7.74

using v=u+at

0=7.74+a*0.55

a=-14  (approx)

Force=ma

=82*(-14)

=-1148 N

Hope this helps.