The equation for a circle with center (h, k) is (x - h)^2 + (y - k)^2 = r^2. If a circle is modeled by the equation x^2 + (y + 6
)^2 = 100, what is the center of the circle?
1 answer:
(x - h)^2 + (y - k)^2 = r^2
x^2 + (y + 6)^2 = 100
we can rewrite this as
(x-0)^2 + (y - -6)^2 = 10^2
the center is (0,-6) and the radius is 10
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