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aleksklad [387]
3 years ago
10

The equation for a circle with center (h, k) is (x - h)^2 + (y - k)^2 = r^2. If a circle is modeled by the equation x^2 + (y + 6

)^2 = 100, what is the center of the circle?
Mathematics
1 answer:
Ronch [10]3 years ago
5 0

(x - h)^2 + (y - k)^2 = r^2

x^2 + (y + 6)^2 = 100

we can rewrite this as

(x-0)^2 + (y - -6)^2 = 10^2

the center is (0,-6) and the radius is 10

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Solution: (2,8)

Using the elimination method set up the system of equations like:

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Eliminate the x-variable by multiplying the top equation by -3

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Combine terms:

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BlackZzzverrR [31]

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Step-by-step explanation:

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3 years ago
The sum of the digits of a two-digit number is 5. If the number is multiplied by 3, the result is 42. Write and solve a system o
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A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit

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The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]

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The system of equations: (two equations for two unknowns)
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Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out

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------------------
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xxTIMURxx [149]

Answer:

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