Since the whole squares that are surrounding 12 are 9 and 16, and their square roots are 3 and 4, we know that the square root of 12 must be in between 3 and 4.
The answer to your question above, I will just illustrate it down.
<span>sqrt(3 x +7 ) = 1 - sqrt(x + 2 )
</span><span>square both sides:
3x + 7 = 1 -2sqrt(x = 2) + x + 2
Then it would become like this,
</span><span>2x + 4 = -2sqrt( x + 2 )
</span>Divide both sides by -2 to eliminate the -2 on the left side with sqrt.
Then <span>square both sides:
x^2 + 4x + 4 = x + 2
</span><span>x^2 + 3x + 2 = 0
</span><span>(x + 2) (x + 1) = 0
</span><span>x=-2, -1 there is no sqrt for-1
</span>so the answer is -2
Answer:
Step-by-step explanation:
<u>Given</u>
- Data: 2, 2, 4, 4, 5, 5, 6, 7, 9, 15
<u>Numbers are already in ascending order</u>
- Lowest value= 2
- Q1 = 4 (median of first part)
- Q2 = 5 (median of full data)
- Q3 = 7 (median of second part)
- Highest value = 15
<u>So the 5 numbers are</u>
Answer:
Option B will be the correct one.
Step-by-step explanation:
See the attached graph.
Here, the graph of f(x) = |x - 7| - 3 is plotted.
Now, from the definition of the absolute value function
f(x) = x - 7 - 3 = x - 10, for x ≥ 7 ............ (1) and
f(x) = - x + 7 - 3 = - x + 4, for x < 7 ............. (2)
Now, for x ≥ 7, the plotted graph passes through the points (7,-3) and (10, 0) and equation (1) satisfies the points.
Again, for x < 7, the plotted graph passes through the points (4,0) and (0,4) and equation (2) satisfies the points.
Hence, option B will be correct one.
Answer:
$1.20c + $3 ≥ $13.50 or $1.20c ≥ $10.50
Step-by-step explanation:
So Janie has $3, and earns $1.20 for each chore. The number of chores she does is c, and she needs $13.50 for the cd. The amount of money she has after doing c number of chores is $1.20c + $3. In order for her to have enough money to buy the cd, the amount of money she has after doing c chores must be greater than or equal to $13.50. This can be written as the inequality:
$1.20c + $3 ≥ $13.50
This will work, but we can simplify this inequality by subtracting $3 from both sides of the equation.
$1.20c ≥ $10.50
$1.20c + $3 ≥ $13.50 or $1.20c ≥ $10.50
I hope this helps. :)
