Answer:
The options are not shown, so i will answer in a general way.
Let's define the variables:
h = number of hats
m = number of mugs.
We know that a total of 1000 items were ordered, then:
h + m = 1000
We also know that we have 3 times more mugs than hats, this can be written as:
m = 3*h
Now we have the system of equations:
h + m = 1000
m = 3*h
To solve these, we usually start by isolating one of the variables in one equation and then replace that in the other equation, but in this case, we already have m isolated in the second equation, then we can replace that in the first equation to get:
h + m = 1000
h + (3*h) = 1000
Now we can solve this equation for h, and find the number of hats ordered.
4*h = 1000
h = 1000/4 = 250
There were 250 hats ordered.
The answer would be C (P=T/2). This can be explained by examining the ratio. If you were to put in the answer of T = 12, then you would be looking for T/2 or 6, assuming we're giving them each half of the amount original held by grandmother.
Answer:
≈ 62.8
Step-by-step explanation:
Using the equal ratios of
= 
, that is
= 
= 5, thus
5 × sector = 100π ( divide both sides by 5 )
sector = 20π = 20 × 3.14 = 62.8 units²
Step-by-step answer:
Please refer to attached image.
1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning
that
angles QPS and QRS are supplementary =>
QPS+QRS=180 =>
QRS = 180 - 74 = 106
2. Triangle RSQ is isosceles with RS=RQ =>
angles RSQ and RQS are congruent.
3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37
4. QP is a diameter => angle QSP is a right-angle.
5. From (3) and (4) above,
angle RSP = 37+90 = 127
6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>
RQP+RSP = 180 =>
x + 127 = 180 =>
x = 180 - 127 = 53 degrees.
Answer:
Step-by-step explanation:
Incomplete presentation of question. Did you want to factor out the greatest common factor (which is 2), obtaining 2(4y - 3)? Or something else? Also: please note that if you use the left parenthesis ) , you MUST also use the right parenthesis ( .
