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3 years ago

What is the tangential acceleration (i.e., the acceleration parallel to the road) of car b?

Mathematics

1 answer:

postnew [5]3 years ago

5 0

the solution is attached below

the tangential acceleration of car A = -9.8m/s^2

car B = - 13.44 m/s^2

car C = -6.16m/s^2

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A company puts bottles of lotions into boxes that are 3 inch cubes. The boxes were then backed into a shipping crate that is a 2

Sonbull [250]

1 foot = 12 inches, so now you add 3 inches until you get 12. you add 3, 4 times toget 12. 3+3=6+3=9+3=12 and do that again for the 2nd foot 3+3=6+3=9+3=12 you added 3, 4 times to get 12 twice so now add 4+4=8
YOUR ANSWER IS 8

8 0

3 years ago

25/8 as a mixed number

Zinaida [17]

<span><span>If you would like to write 25/8 as a mixed number, you can do this using the following step:</span><span>

25/8 = 3 1/8

Result: 25/8 equals to 3 1/8 as a mixed number.</span></span>

3 0

3 years ago

Read 2 more answers

At a big cat reserve, a male Bengal tiger weighs more than a female Bengal tiger. The male tiger weighs 445 pounds. The differen

kolbaska11 [484]

The value of f is 348 pounds.

Given

At a big cat reserve, a male Bengal tiger weighs more than a female Bengal tiger.

The male tiger weighs 445 pounds.

The difference in the weight of the tigers is 97 pounds.

<h3>Difference;</h3>

The meaning of DIFFERENCE is the quality or state of being dissimilar or different.

The zookeeper created the bar diagram and the equation below is given as:

$\rm 445=f+97$

On solving the equation the value of f is;

$\rm 445=f+97\\\\f = 445-97\\\\f= 348$

Hence, the value of f is 348 pounds.

To know more about the differences click the link given below.

brainly.com/question/11572024

4 0

2 years ago

Read 2 more answers

Use the identity below to complete the tasks: a3 − b3 = (a − b)(a2 + ab + b2) When using the identity for the sum of two cubes t

saveliy_v [14]

Answer:

a= $5q^ {2}$

b= $r^{2}s$

Step-by-step explanation:

Here $125q^{6}$ is like the $a^{3}$ in the general formula.

So we can write $125q^{6}$ as:

$(5q^ {2} )^{3}$

We can also write $r^{6} s^{3}$ as:

$(r^{2}s)^{2}$

Therefore:

a³= $(5q^ {2} )^{3}$

b²= $(r^{2}s)^{2}$

8 0

3 years ago

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Can anyone help me out

alexandr402 [8]

Maximum profit due to the feasibility graph....we take where the two lines cross...(6,5). These figures are substituted into the equation and the result is the max profit...

p = 3x + 2y
p = 3(6) + 2(5)
p = 18 + 10
p = 28

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3 years ago