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nikklg [1K]
4 years ago
14

Why sample size is important in determining probability?

Mathematics
1 answer:
SVETLANKA909090 [29]4 years ago
3 0

Sample size is important because

(1) sample size includes all possible outcomes

(2) it also includes number of favourable outcomes

for finding probability , we use formula

probability= ( number of favourable outcomes)/(total number of possible outcomes)

We can get both in sample size

it will help us to find probability

For example:

If a dice is rolled , we get sample space

sample space = { 1 , 2, 3, 4, 5, 6}

Suppose, we want to find probability of getting even number

so, favourable outcomes = {2,4,6}=3

total number of possible outcomes={1,2,3,4,5,6}=6

so, probability = 3/6 =1/2


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Sociologists say that 85% of married women claim that their husband's mother is the biggest bone of contention in their marriage
hoa [83]

Answer:

(A) 0.377,

(B) 0.000,

(C) 0.953,

(D) 0.047

Step-by-step explanation:

We assume that having a bone of intention means not liking one's Mother-in-Law

(A) P(all six dislike their Mother-in-Law) = (85%)^6 = (.85)^6 = 0.377

(B) P(none of the six dislike their Mother-in-Law) =

(100% - 85%)^6 =

0.15^6 =

0.000

(C) P(at least 4 dislike their Mother-in-Law) =

P(exactly 4 dislike their Mother-in-Law) + P(exactly 5 dislike their Mother-in-Law) + P(exactly 6 dislike their Mother-in-Law) =

C(6,4) * (.85)^4 * (1-.85)^2 + C(6,5) * (.85)^5 * (.15)^1 + C(6,6) * (.85)^6 = (15) * (.85)^4 * (.15)^2 + (6) * (.85)^5 * .15 + (1) * (.85)^6 =

0.953

(D) P(no more than 3 dislike their Mother-in-Law) =

P(exactly 0 dislikes their Mother-in-Law) + P(exactly 1 dislikes her Mother) + P(exactly 2 dislike their Mother-in-Law) + P(exactly 3 dislike their Mother-in-Law) =

C(6,0) * (.85)^0 * (.15)^6 + C(6,1) * (.85)^1 * (.15)^5 + C(6,2) * (.85)^2 * (.15)^4 + C(6,3) * (.85)^3 * (.15)^3 =

(1)(1)(.15)^6 + (6)(.85)(.15)^5 + (15)(.85)^2 *(.15)^4 + (20)(.85)^3 * (.15)^3 =

0.047

3 0
3 years ago
The chairman of the community bazaar is assigning people to chair committees. How many different ways can the 6 people be assign
iren [92.7K]

The 6 people be assigned in 720 different ways to chair the subcommittees.

<u>Step-by-step explanation:</u>

Given that,

  • There are 6 people to be assigned to the chair committees.
  • So, you need to find that in how many ways they can be assigned their seats.

This can be calculated by Permutation.

The number of arrangements in which the order of the objects matters is calculated as permutation.

The permutation is given as ⇒ P = n!

Here we can 6 people to be assigned. Therefore n = 6.

⇒ Number of ways can be arranged = 6!

⇒ 6×5×4×3×2×1

⇒ 720

∴ The 6 people be assigned in 720 different ways to chair the subcommittees.

4 0
4 years ago
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