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3 years ago

3. a pitcher of water contains 1\4 liters if water the water is poured equally into 5 glasses.

1 answer:

8 0

Figure out how much water is in one liter and then divide the amount by 4, then figure out how many milliliters are in a full liter and divide it by 4 and you will get your answer.

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A number cube has faces numbered 1 to 6. What is true about rolling the number cube one time? Select three options. S = {1, 2, 3

Marat540 [252]

Answer:

The correct answers are the options B. ; C. ; D.

Step-by-step explanation:

A numbered cube has face from 1 to 6.

The set S = {1, 2, 3, 4, 5, 6}.

A. If A is a subset of S, A could be {0, 1, 2}. This statement is false as A is a subset of B and A contains the element {0} which is not in S.

B. If A is a subset of S and A is given by {5, 6}. This statement is true as A elements of A are also in S.

C. If a subset A represents the complement of rolling a 5, then A = {1, 2, 3, 4, 6}. This statement is even true as A should contain all numbers from 1 to 6 except 5.

D. If a subset A represents the complement of rolling an even number, then A = {1, 3}. This statement is true as the numbers complement of an even number are 1, 3 and 5.

5 0

3 years ago

Read 2 more answers

Allison has three containers with 25 crayons in each. She also has four boxes of markers with 12 markers in each box. She gets 1

Advocard [28]

25x3=75
4x12=48
48-10=38

75 crayons and 38 markers

3 0

4 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago

Write out the rule and fill in the empty boxes. Complete the function table.

Ksenya-84 [330]

Answer:

Input divided by 3 is output 28 and 38 are the outputs in the blank boxes

Step-by-step explanation:

33 divided by 3 is 11 126 divided by 3 is 42

4 0

3 years ago

Read 2 more answers

If line TW is parallel to line SX , m ∠ 1 = 59°, and m ∠ 6 = 72°, what is m ∠ 8?

choli [55]

Angle 1 and Angle 8 are Alternate Exterior Angles. Therefore, by the Alternate Exterior Angle Theorem, the measure of angle 8 is also 59 degrees. Hope this helped!

7 0

4 years ago