Is 6 a factor of 30 true or false

Mathematics

2 answers:

beks73 [17]3 years ago

6 0

true 6x5=30 15x2=30 so forth

Gwar [14]3 years ago

3 0

It is true, 6*5 is 30

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The circumference (C) C of a swimming pool is 56 feet. Which formula can you use to find the diameter (d) d if you know that C=π

LiRa [457]

Since you are solving for diameter, and the equation is given to you, just isolate the variable for diameter (d).

(C)/π = (πd)/π

d = C/π is your formula you will use.

Plug in 56 for C

d = 56/π

d = ~17.825

3 0

3 years ago

Read 2 more answers

2x2 + 2x-4?

nexus9112 [7]

Answer:

2x^2 +2x-4
——————
2x^2-4x+2

Factor out 2 from the expression

2(x^2+x-2)
—————-
2(x^2-2x+1)

Write x as a difference

2(x^2x-x-2)
—————-
2(x^2-2x+1)

Use a^2-2ab+b^2=(ab)^2

2(x^2x-x-2)
—————-
2(x-1)^2

Reduce the fraction with 2

x^2x-x-2
—————-
(x-1)^2

Factor out x from the expression

X*(x^2)-x-2
—————-
(x-1)^2

Factor out negative sign from the expression

X*(x+2)-(x-2)
—————-
(x-1)^2

Factor out x+2 from the expression

(x+2)(x-1)
—————-
(x-1)^2

Simplify the expression

x+2
——
x-1

6 0

3 years ago

suppose X and Y are independent random variables, both with normal distributions. If X has a mean of 45 with a standard deviatio

djyliett [7]

Answer:

0.9772 = 97.72% probability that a randomly generated value of X is greater than a randomly generated value of Y

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu_X = 45, \sigma_X = 4, \mu_Y = 35, \sigma_Y = 3$

What is the probability that a randomly generated value of X is greater than a randomly generated value of Y

This means that the subtraction of X by Y has to be positive.

When we subtract two normal variables, the mean is the subtraction of their means, and the standard deviation is the square root of the sum of their variances. So

$\mu = \mu_X - \mu_Y = 45 - 35 = 0$