Start by graphing each line.
• Because the first inequality is smaller than, it will have a dotted (- - -) line.
• Because the second inequality is smaller than or equal to, it will have a solid line (---).
Then, plug in points to see where your shading will go. If the statement is true (x = x), you will shade that area along the line.
0 is less than 2.
Do the same step for the other equation. Your solution to the problem is any point that lies between the shading from both inequalities (where the blue and red meet).
Answer:
r = 46
Step-by-step explanation:
as in the attachment, have created the CEF triangle by stretching lines.
hope it helps:)
good luck:)
It holds the legs up. there is a right angle which is the little box in the 90 degree corner:) the hypotenuse is always the longest part on the triangle which you can not simplify:) so the right triangle has legs that you can simplify:)
Answer:
Answer is D. Please thank me and give 5 stars
Answer:
Step-by-step explanation:
hello,
I understand that there are only 4 cards and then the player draw a card out of the 4 cards, replace it so the second draw is still out of the 4 cards
<u>How many ways can you draw two cards?</u>
as the first card is replaced, this is 4*4=16
so there is 16 possibles ways
hearts hearts
hearts clubs
hearts diamonds
hearts spades
clubs hearts
clubs clubs
clubs diamonds
clubs spades
diamonds hearts
diamonds clubs
diamonds diamonds
diamonds spades
spades hearts
spades clubs
spades diamonds
spades spades
<u>out of these 16 ways, how many have same colour for both cards?</u>
I assume that there are only two colours Red and Black, so we can have
only 8 ways so the first probability is 8/16 = 1/2
<u>out of these 16 ways, how many are red ace first and black ace?</u>
There are 4 ways so the probability is 4/16 = 1/4
hope this helps
