Question

Dr cheeks tries to run at least 45 rotation on her hamster wheel each week she has already run 6 rotation. which inequality shows how many rotations

Answer 1

Let x be the number of rotations left to run, then
x + 6 ≥ 45

Answer 2

Solution:

Minimum number of rotation that Dr cheeks tries to run on his wheel each week = 45

1 Week ≥ 45

Number of rotation already ran by Dr cheek = 6 rotation

It is not given that whether these rotations have to complete at which duration of time.

Supposing that Dr. cheek has done 6 rotations on first day of week.

Let number of rotation done on each day = x

Number of days in a week = 7

→ 6 x + 6 ≥ 45

→ 6 x ≥ 45 -6

→ 6 x ≥ 39

→→ x≥ $\frac{39}{6}$

→→x≥ $\frac{13}{2}$=7 rotation (Approx) each day