Compute. 52 · 52 Please

Round your answer to the nearest hundredth. Pro с 2 в Mis Pro Tea

Snezhnost [94]

Answer:

do you still need help?

Step-by-step explanation:

8 0

3 years ago

2 Points

Digiron [165]

Answer:

718,200 boxes

Step-by-step explanation:

Given the dimension of the storage space = 300ft×200ft×30ft

Dimension of each box = 20in×18in×12in

In order to determine the number of boxes Graphic DesignWorks is able to store, we will divide the Dimension of the storage space the dimension of the box.

Number of boxes = Dimension of storage space/dimension of boxes

We need to convert the dimension of boxes from inches to feet

1inch = 0.0833ft

20inches = 20×0.0833 = 1.666ft

18inches = 18×0.0833 = 1.499ft

12inches = 12×0.0833 = 0.9996ft

Number of boxes = 300×200×30/1.666×1.499×0.9996

Number of boxes = 1800000/2.496

Number of boxes = 721,153.85boxes

Based on the value, the best estimate that is close to the gotten value will be 718,200 boxes

3 0

3 years ago

A pair of jeans cost 89. A jean jacket costs twice as much. What is the total cost of a jean jacket and 4 pairs of jeans?

iVinArrow [24]

Jeans=$89 jean jacket=$(89x2)
$178
$(89x4+178)
89
  x4
$ (276 + 178)= $454

total cost = $454

7 0

3 years ago

PLZ Help!!!! what is m A. 23 B. 20 C. 43 D. 63

yan [13]

I believe its c also.

3 0

3 years ago

Match the function in the left column with its period in the right column.

kiruha [24]

The results for the matching between function and its period are:

Option 1 - Letter D
Option 2 - Letter A
Option 3 - Letter C
Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

$\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}$

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}$

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi$

Thus, the option 1 matches with the letter D.

2) Option 2

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}$

Thus, the option 2 matches with the letter A.

3) Option 3

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi$

Thus, the option 3 matches with the letter C.

4) Option 4

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}$

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0

2 years ago