We can write it az 2 minus sum of p and 6
As p and 6 are in bracket therefore first we add p and 6 and then subtract the sum from 2
Here we want to find the equation of the line containing the median CP.
P, being the midpoint of AB can be found using the midpoint formula as:
.
The slope m of the line through CP can be found by the slope formula using points C(18, -8) and P(0, 1):
.
Now, we can write the equation of the line with slope -1/2, passing through
P(0, 1):
.
Answer:
Answer:
<h2>x = -2 or x = 4</h2>
Step-by-step explanation:
The zeros:
(x + 2)(x - 4) = 0 ⇔ x + 2 = 0 or x - 4 = 0
x + 2 = 0 <em>subtract 2 from both sides</em>
x = -2
x - 4 = 0 <em>add 4 to both sides</em>
x = 4
Answer:
a) 0.0081975
b) 0.97259
Step-by-step explanation:
The line width for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
a. What is the probability that a line width is greater than 0.62 micrometer?
z = 0.62 - 0.5/0.05
z = 2.4
Probability value from Z-Table:
P(x<0.62) = 0.9918
P(x>0.62) = 1 - P(x<0.62)
= 0.0081975
b. What is the probability that a line width is between 0.4 and 0.63 micrometer?
For 0.4
z = 0.4 - 0.5/0.05
= -2
Probability value from Z-Table:
P(x = 0.4) = 0.02275
For 0.63
z = 0.63 - 0.5/0.05
= 2.6
Probability value from Z-Table:
P(x = 0.63) = 0.99534
P(x = 0.63) - P(x = 0.4)
= 0.99534 - 0.02275
= 0.97259
c. The line width of 90% of samples is below what value?
As you can observe, the divisor, 6582, is greater than the dividend, 32. In this case, the answer is less than 1. Technically, the answer is $0 with a remainder of 6,582. However, I think the more logical question would be 6582 divided by 32. If so, the solution is as follows:
205
-------------------------
32 | 6582
- 64
------------------
18
- 0
---------------
182
- 160
----------
22
The answer is $205 with a remainder of 22.
