Answer:
4pq(p³+q³)
Step-by-step explanation:
Exactly 5 game would be when 4 wins and 1 loss of a particular person
loss has to be one of the first 4 games
A wins: qp⁴ + pqp³ + p²qp² + p³qp
= qp⁴ + qp⁴ + qp⁴ + qp⁴ = 4qp⁴
B wins: pq⁴ + qpq³ + q²pq² + q³pq
= pq⁴ + pq⁴ + pq⁴ + pq⁴ = 4pq⁴
A wins or B wins:
4pq⁴ + 4qp⁴ = 4pq(q³+p³)
Answer:
10
Step-by-step explanation:
Since each ornament takes 1/4 of a piece of Bristol board we divide 2 1/2 by 1/4
2 1/2 = 5/2
(5/2)/(1/4) = 20/2 = 10
Answer:
No solution exists
Step-by-step explanation:
#1.
[4x = -12y + 16 and x + 3y = 4]
One answer
#2.
Here, y = 4x + 3
y - 4x = 3
Multiply by 2,
2y - 8x = 6
Compare with second equation,
6 ≠ 3
In short, System of Equation does not have any solution. [ Option D ]
#3.
2y=6
3x-6y=18
Divide first equation by 2: y=3
Substitute y=3 into second equation: 3x-6(3)=18
Solve for x: 3x=36 x=12
Therefore there is only one solution: x=12 y=3
#4.
y - 7x = -14
7y - 49x = -2
Rewrite the first equation as "y =" so that it can be substituted into the second equation and solve for x.
y = 7x - 14
7(7x - 14) - 49x = -2
49x - 98 - 49x = -2
-98 = -2
Since the variables cancel and the equation is not true there is no solution.
The lines are parallel and will not intersect.
2x - 9x = 14 (Careful next time you accidentally added an "equal" next to the 2)
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Simplify
2x-9x=<span>14
</span><span>2x+-9x</span>=<span>14
</span>--------------------------------------------
Combine the like-terms
<span>(<span>2x+-9x</span>)</span>=<span>14
</span><span><span>-7x</span></span>=<span>14
</span>--------------------------------------------------
Now divide -7 to each side
-7x ÷ -7 = 14 ÷ -7
x = -2
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x = -2 is your answer