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Klio2033 [76]
3 years ago
8

Sean was dividing 0.45 by 0.75.

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0
Sean was dividing 0.45 by 0.75.According to the given choices, which one will be correct. First, let us solve the given division problem:
=> 0.45 / 0.75 = 0.6 is the quotient. Thus the answer would be:

B. 
It will be greater than 0.45. 

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Jon invests $4,100 into an account that pays 5 percent simple interest each year.what is the total balance in the account after
AlladinOne [14]
% Interest = 5%
 Principal Amount = $4100
Period Of Pay = 3 yrs

Interest Amount
5/100 × 4100 × 3 
  =615

Amount After Interest
4100 + 615 = 4715

Answer = 4715
7 0
3 years ago
Read 2 more answers
Find cos(2115°) and sin(2115°). Identify the measure of the reference angle.
ivolga24 [154]

Answer:

Cos(2115°) =1/√2

Sin(2115°) = -1/√2

Step-by-step explanation:

We have to find the values of Cos (2115°) and Sin (2115°).

Now, 2115° can be written as (23×90°+ 45°).

Therefore, the angle 2115° lies in the 4th quadrant where Cos values are positive and Sin values are negative.

Hence, Cos (2115°) = Cos(23×90° +45°) =Sin 45° {Since 23 is an odd number, so the CosФ sign will be changed to SinФ} =1/√2 (Answer)

Again, Sin (2115°) = Sin(23×90° +45°) = -Cos 45° {Since 23 is an odd number, so the SinФ sign will be changed to CosФ} = -1/√2 (Answer)

Now, the required reference angle is 45°. (Answer)

8 0
3 years ago
Kon'nichiwa !!<br><br>What's the Value of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%203%20%5Ctimes%20-%20%203%7D%2
NeX [460]

Answer:

3 answer

Step-by-step explanation:

hope it helps!!!

3 0
3 years ago
Read 2 more answers
LINDITUETID
Setler79 [48]
Sorry this answer is unacceptable
8 0
3 years ago
A quantity x has cumulative distribution function p(x) = x − x2/4 for 0 ≤ x ≤ 2 and p(x) = 0 for x &lt; 0 and p(x) = 1 for x &gt
34kurt
F_X(x)=\begin{cases}0&\text{for }x2\end{cases}

Recall that the PDF is given by the derivative of the CDF:

f_X(x)=\dfrac{\mathrm dF_X(x)}{\mathrm dx}=\begin{cases}1-\dfrac x2\\\\0&\text{otherwise}\end{cases}

The mean is given by

\mathbb E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\int_0^2\left(x-\dfrac{x^2}2\right)\,\mathrm dx=\frac23

The median is the number M such that F_X(x)=\mathbb P(X\le M)=\dfrac12. We have

F_X(M)=M-\dfrac{M^2}4=\dfrac12\implies M=2\pm\sqrt2

but both roots can't be medians. As a matter of fact, the median must satisfy 0\le M\le2, so we take the solution with the negative root. So M=2-\sqrt2 is the median.
3 0
3 years ago
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