Answer:
V_rocket = 44
ft^3 = 138.2 ft^3
Step-by-step explanation:
Volume of cone
V_cone = (1/3)*(
*(radius^2))*h
radius = 2ft
h = height of the cone = 3 ft
pi = 3.1416
V_cone = 4
ft^3
Volume cylinder
V_cylin = (
*(radius^2))*h_cyl
h_cyl = height of the cylinder = 10 ft
V_cylin = 40
ft^3
Volume rocket
V_rocket = V_cone + V_cylin = 4
ft^3 + 40
ft^3
V_rocket = 44
ft^3 = 138.2 ft^3
7+14+15+5+8 + 9 =58 yard
answer 58 yd
Answer: The sailboat is at a distance of 15 km from the port.
Step-by-step explanation: Given that a sail boat leaves port and sails 12 kilometers west and then 9 kilometers north.
We are to find the distance between the sailboat from the port in kilometers.
Since the directions west and north are at right-angles, we can visualize the movement of the sailboat in the form of a right-angled triangle as shown in the attached figure.
The sailboat moves leaves the port at P and reach O after sailing 12 km west. From point O, again it moves towards north 9 km and reach the point S.
PS = ?
Using the Pythagoras theorem, we have from right-angled triangle SOP,
Thus, the sailboat is at a distance of 15 km from the port.
Answer:
n + 11 and 11 + n
Step-by-step explanation:
Let n be the unknown number,
n is increased by 11,
That is, n + 11
By the commutative property of addition,
The expression would be,
11 + n
For drawing a model that shows n + 11
Take two boxes in which first shows n and second shows 11 and add them,
Similarly, for showing 11 + n, take first box that shows 11 and second box that shows n then add them.
Answer:
The answer is 68°
Step-by-step explanation:
<h3>
<u>Given</u>;</h3>
- A right angled-triangle IGH.
- where, m∠G = 90°
<h3><u>To </u><u>Find</u>;</h3>
We know that
tan θ = Opp ÷ Adj
tan θ = 5 ÷ 2
tan θ = 2.5
tan θ = 68.2 ≈ 68
We know that tan 68 = 2.5
Thus, The m∠I is 68°
<u>-TheUnknownScientist 72</u>