Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
The three (3) possible adverse effects of this medication and nursing interventions/client are the following;
First is Prevention of nocturnal enuresisSecond is Maintenance of appropriate body water content in diabetes insipidus And the last is Control of bleeding in certain types of hemophilia or von Willebrand's disease(Davis's Drug Guide for Nurses 14th Edition)
Answer:
talk to your teacher
Explanation:
talk to your teacher about your missing assignment. they will look for it for you, but if they can't find it, you might have to redo the assignment. they might also give you an exemption on the assignment, but that's unlikely.
if you're worried about talking to them face-to-face, you could email them.
Carbohydrates (<span>Macromolecule which is used for structural purposes for plants and animals and are good for short-term energy storage)</span>