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Mila [183]
3 years ago
6

Y=-3x-3

le" class="latex-formula">

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Let's find X. Since both equations are equal to y, they are equal to themselves.

-3x-3=-3; we just need to solve from here. -3x-3=-3; let's add 3 to both sides. -3x=0; this means that 0 is X.

Let's use a graph to check.

So, y is -3.

So, (0, -3) is when the two lines intersect and it's our solution.

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Answer:

\dfrac{(a+b)}{ab}

Step-by-step explanation:

The given expression is :

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It can be solved as follows :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}

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3 years ago
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Answer:

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