Answer:
The complete question is:
At a university, 13% of students smoke.
a) Calculate the expected number of smokers in a random sample of 100 students from this university:
b) The university gym opens at 9 am on Saturday mornings. One Saturday morning at 8:55 am there are 27 students outside the gym waiting for it to open. Should you use the same approach from part (a) to calculate the expected number of smokers among these 27 students?
Part a is easy, because is a random sample, we can expect that just 13% of these 100 students to be smokers, and 13% of 100 is 13, so we can expect 13 of those 100 students to be smokers.
b) This time we do not have a random sample, our sample is a sample of 15 students who go to the gym in the early morning, so our sample is biased. (And we do not know if this bias is related to smoking or not, and how that relationship is), so we can't use the same approach that we used in the previous part.
Answer:
C.
Step-by-step explanation:
So basically set (10x-13) equal to (3x+22) and then solve for x
x=5
Plug 5 into the equations
(10(5)-13)=37
(3(5)+22)=37
These two angles are congruent due to the triangle being isosceles
37+37=74
All angles in a triangle are equal to 180 degrees
Therefore 180-74=106
Angle JKL= 106 degrees
Hope this helps :)
Answer:
y = x - 8
Step-by-step explanation:
y = x - 8
Check your answer using (0, -8):
y = x - 8
-8 = 0 - 8
-8 = -8
This statement is true
Also, view the attached graph.
Hope this helps!
<h3>Answer:</h3>
56 m²
<h3>Explanation:</h3>
The altitude from point B to segment CP is the same for ∆BMP as for ∆BMC. Since both have the same base length (MP = MC), both have the same area, 21 m². Hence the area of ∆CPB is (21+21) m² = 42 m².
The altitude from point C to segment AB is the same for ∆CPA as for ∆CPB, so the areas of those triangles will have the same proportion as the base segments AP and BP. That is, ...
... AACPA : ACPB = PA : PB = 1 : 3
The ratio of ACPB to the total is then ...
... ACPB : (ACPA +ACPB) = 3 : (1+3) = 3 : 4
The area of ∆ABC is the total of the areas of the smaller triangles CPA and CPB, so we have
... ACPB : AABC = 3 : 4
... AABC/42 m² = 4/3 . . . . . rearranging slightly and substituting for ACPB
... AABC = (42 m²)×(4/3) . . . . multiply by the denominator
... AABC = 56 m²
Let "x" be the scaling factor
3x mums
2x dads
mums appt. + dads appt = total appointments
3x + 2x = 500
5x = 500
x = 100
300 appointments with mums
200 appointments with dads
