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lesya692 [45]
3 years ago
5

What are two common uses of igneous rocks? given extra points!

Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0
<span>Constructing buildings and statues. Also forming volcano's.</span>
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How do you find the surface area for this one and what is the surface area for that?
klemol [59]
<span>First find the area of two sides (Length*Height)*2 sides, 60. Then find the area of adjacent sides (Width*Height)*2 sides, 43.2. And then find the area of ends (Length*Width)*2 ends, 72. Lastly add the three areas together to find the surface area, 175.2.</span>
6 0
3 years ago
Read 2 more answers
5. What is the probability that in a random sample of 500 adult Americans, less than 51% admit to cheating?
stealth61 [152]

The right answer is b

Step-by-step explanation:

You do you do the calculations you get that answer

5 0
3 years ago
A car dealership pays a wholesale price of $14,000 to purchase a car. They sell the car for
harkovskaia [24]

Answer:

115% or 15%

Step-by-step explanation:

14000=100%

16100=X%

14000/100=140

16100/140=115

so 115% or 15%

3 0
3 years ago
Solve for x:-ax+3b&gt;5
Salsk061 [2.6K]
Our current equation is:
-ax + 3b > 5

Our objective is to solve for x, so let's first get -ax by itself.
Subtract 3b from both sides.

-ax > -3b + 5
Now, we have -a multiplying x, so we need to perform the opposite order of operations (like previously shown with 3b).
Divide both sides by -a.
Remember to flip the inequality when multiplying or dividing by a negative.

x <_ (-3b + 5)/-a is your final answer.

I hope this helps!
7 0
3 years ago
A pot is being used to boil off 1 kg of water. The specific energy required to cause the phase change is 2297 kJ/kg. Assuming th
Daniel [21]

Answer:

58 seconds

Step-by-step explanation:

Given:

Initial mass of water = 1 kg

Specific energy = 2297 kJ/kg

Heat supplied by the stove = 20 kJ/s

Now,

Half water is to be vaporized i.e 0.5 kg

Thus, heat required for vaporizing 0.5 kg water = mass × specific heat

or

heat required for vaporizing 0.5 kg water = 0.5 × 2297 = 1148.5 kJ

Therefore,

time taken to provide the required heat = \frac{\textup{Heat required}}{\textup{Heat supplied per second}}

or

time taken to provide the required heat = \frac{\textup{1148.5 kJ}}{\textup{20 kJ/s}}

or

time taken to provide the required heat = 57.425 ≈ 58 seconds

8 0
3 years ago
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