Question

Will a 9/32 inch diameter pin fit into a reamed hole with a diameter of 0.278 inch? (Do not round off your answer and express it in fraction
form)

Answer 1

Answer:

No, it won't

Step-by-step explanation:

Given

$Pin\ diameter = \frac{9}{32}$

$Reamed\ hole\ diameter = 0.278$

Required

Will the pin fit into the reamed hole?

For the pin to fit into the reamed hole, the diameter has to be smaller than that of the reamed hole.

In other words;

The pin will fit in if it satisfies the following condition

$Reamed\ hole - Pin > 0$

$Reamed\ hole - Pin = 0.278 - \frac{9}{32}$

Convert decimal to fraction

$Reamed\ hole - Pin = \frac{278}{1000} - \frac{9}{32}$

Simplify fraction to lowest term

$Reamed\ hole - Pin = \frac{139}{500} - \frac{9}{32}$

Take LCM

$Reamed\ hole - Pin = \frac{1112 - 1125}{4000}$

$Reamed\ hole - Pin = \frac{-3}{4000}$

This doesn't satisfy the condition $Reamed\ hole - Pin > 0$

Because $\frac{-3}{4000} < 0$

So, we can conclude that the Pin will not fit into the reamed hole