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Galina-37 [17]
3 years ago
5

Helppppp plzz thnaksss Are these correct??

Mathematics
1 answer:
givi [52]3 years ago
7 0
The first picture is correct, the triangle was dilated by a factor of 1/3 and then shifted 2 units down.

The second picture is also correct, because the dots are higher as they move to the right, it is a positive association and they follow a linear line.
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In ΔPQR, the measure of ∠R=90°, QR = 91 feet, and RP = 26 feet. Find the measure of ∠Q to the nearest tenth of a degree.
trapecia [35]

Answer:

Step-by-step explanation:

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15.9454=15.9

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3 years ago
Write this in factored form<br><br> 2a^+11a+5
True [87]
I hope this helps you

3 0
3 years ago
-72=-9s-45 can’t seem to find the answer to this
Cerrena [4.2K]

-72=-9s-45 also equals -9s-45=-72

-9s - 45 + 45 = - 72 + 45

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Hope this helped!

4 0
4 years ago
1-cos2a/1+cosa if 1/3 how much sin²a
Helen [10]

Answer:

(1-cos2A) /(1+cos2A) =tan²A

Proof:

We know that,

cos(A+B) =cosA.cosB-sinA.sinB

=>cos2A=cos(A+A)

=>cos2A=cosA.cosA - sinA.sinA

=>cos2A=cos²A-sin²A

=>cos2A=(cos²A-sin²A)/(cos²A+sin²A

Since {cos²A+sin²A=1}

Divide the numerator & the denominator by (cos²A) to get,

cos2A = {(cos²A-sin²A) ÷cos²A} / {(cos²A+sin²A) ÷cos²A}

cos2A ={(1-tan²A)/(1+tan²A)}

Then,

1-cos2A = 1-[{(1–tan²A)/(1+tan²A)}]

1-cos2A =(1+tan²A-1+tan²A)/(1+tan²A)

1-cos2A=(2tan²A)/(1+tan²A)

And now.......

1+cos2A=1+[{(1-tan²A)/(1+tan²A)}]

1+cos2A={1+tan²A+1-tan²A}/{1+tan²A}

1+cos2A=2/(1+tan²A)

So now,

(1-cos2A)/(1+cos2A)= {2tan²A/(1+tan²A)}÷{2/(1+tan²A)}

={(2tan²A)(1+tan²A)}÷{2(1+tan²A)}

=tan²A

Step-by-step explanation:

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3 0
4 years ago
Arrange the steps in the correct order to perform this subtraction problem.
V125BC [204]

Answer:D

Step-by-step explanation:The simplified version of the equation is D and the answer of the equation is 610

3 0
4 years ago
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