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3 years ago

9

Janet invested $10,000, part at 2% and part at 12%. if the total interest at the end of the year is $600, how much did she inves

ted at 2%

1 answer:

Ivan3 years ago

3 0

Janet invested $6000 at 2 %.

Let <em>x</em> = amount invested at 2 %. Then 10 000 - <em>x</em> = amount invested at 12 %

interest at 2 % + interest at 12 % = 600

0.02<em>x</em> + 0.12(10 000 –<em> x</em>) = 600

0.02<em>x</em> + 1200 – 0.12<em>x</em> = 600

0.10<em>x</em> = 600

x = 600/0.10 = 6000

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