Question

Determine whether the function below is an even function, an odd function, both, or neither. f(x)=x^2+3 Answers choices: A. Odd function B. Even function C. Neither even nor odd D. Both even and odd

Answer 1

The answer is: B. Even function.

The explanation for this exercise is shown below:

1. You must substitute $x$ with $-x$ in the function:

$f(x)=x^{2} +3\\ f(-x)=(-x)^{2} +3\\ f(-x)=x^{2} +3$

2. As you can see, $f(-x)=f(x)$, therefore it is an Even function.

Answer 2

Answer:

B. Even Function

Step-by-step explanation:

I just took this test on plato and it is correct.

Even function: a function in which f(-x) = -f(x) for all values. When graphed it is symmetric about the origin. This equation meets all of the criteria for an even function.