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IceJOKER [234]
3 years ago
13

If cosA = 3/5 and A ∈ (630,720), find sin2A

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

- \frac{24}{25}

Step-by-step explanation:

Given 630 < A > 720 then A is in the fourth quadrant where

cosA > 0 and sinA < 0

Given

cosA = \frac{3}{5} = \frac{adjacent}{hypotenuse}

Then the triangle is a 3- 4 - 5 with opposite side 4, thus

sinA = - \frac{opposite}{hypotenuse} = - \frac{4}{5}

Using the trigonometric identity

sin2A = 2sinAcosA

         = 2 × - \frac{4}{5} × \frac{3}{5}

         = \frac{2(-4)(3)}{5(5)} = - \frac{24}{25}

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Simplify each expression.
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Answer:

is number 3

Step-by-step explanation:

see explanation on the attached

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8 0
3 years ago
Solve each system of equation<br> Y=-3x+5 <br> 5x-4y=-3
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Y = -3x + 5
5x - 4y = -3

   5x - 4(-3x + 5) = -3
5x + 4(3x) - 4(5) = -3
     5x + 12x - 20 = -3
             17x - 20 = -3
                   + 20  + 20
                    17x = 17
                     17     17
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                        y = -3(1) + 5
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                        y = 2
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6 0
4 years ago
If x = (7+4√3), then the value of x^2 + 1/x^2 is​
Blizzard [7]

Answer:

194.

Step-by-step explanation:

x = (7+4√3)

x^2 =  x = (7+4√3)^2

= 49 + 48 + 56√3

= 97 + 56√3

x^2 + 1/x^2 =    97 + 56√3 + 1/(97 + 56√3)

= 194.

5 0
3 years ago
Given the figure below, 11 || 12. Also m_g = 4x + 6 and mZh=6x - 36.
lara [203]

Answer:b c eStep-by-step explanation:

8 0
3 years ago
What is the slope of the line containing the midpoint of the segment with endpoints at $(2, 4)$ and $(0, -2)$ and the midpoint o
oksian1 [2.3K]

The Midpoint 1 = (1,1), Mid point 2 = (3,3 ) and slope is 1 of the given points of the line.

<h3>What is the slope of line?</h3>

The slope of a line segment is a measure of the steepness of the line segment. It is the ratio of rise (the change in vertical height between the endpoints) over run (the change in horizontal length between the endpoints.

The slope of a line is a measure of its steepness. Mathematically, slope is calculated as "rise over run" (change in y divided by change in x).

Whenever the equation of a line is written in the form y = mx + b, it is called the slope-intercept form of the equation. The m is the slope of the line.

Midpoints of 1 line segment are -

= (2+0 / 2 , 4-2 / 2)

= (1,1)

Mid points of line 2 =

= (5+1 / 2, 1+5 / 2)

= (3,3)

slope  -

The required slope = rise / run

= (y1-y2)/(x1-x2)

= (1-3)/(1-3)

= 1

Therefore, the Midpoint 1 = (1,1), Mid point 2 = (3,3 ) and slope is 1 of the given points of the line.

To learn more about slope and mind-points from the given link

brainly.com/question/5792883

#SPJ4

6 0
2 years ago
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