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Alexus [3.1K]
4 years ago
6

Someone please help me! This confuses me!!

Mathematics
1 answer:
Maksim231197 [3]4 years ago
4 0
X^3 - 5 = -32

x^3 = -32 + 5

x^3 = -27

Now -27 = (-3)^3   so the answer is  x = -3
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Lauren save $84 more than Fiona. 1 fifth Of Lauren's saving was the same as 3 eights of fiona's Saving. How much did Lauren and
muminat

Answer:

Lauren's saving=$180

Fiona's saving=$96

Step-by-step explanation:

Let the saving's of fiona be x

Now given that the savings of lauren is $84 more than fiona which means the saving's of lauren is x+84

Given 1 fifth Of Lauren's saving was the same as 3 eights of fiona's Saving

\frac{1}{5}(lauren's saving)=\frac{3}{8}(fiona's saving)

\frac{1}{5}(x+84)=\frac{3}{8}(x)

8x+672=15x

7x=672\\x=96

Therefore the saving's of fiona is $96 and the saving's of Lauren's is 96+84=$180

7 0
3 years ago
Dina took 12 hours to read a 600 page book What was her page per minute rate?
jok3333 [9.3K]

50 divide to find the answer

4 0
3 years ago
A man starts at a point A and walks 18 feet north. He then turns and walks due east at 18 feet per second. If a searchlight plac
34kurt

Answer:

1/10 per sec

Step-by-step explanation:

When he's walked x feet in the eastward direction, the angle Θ that the search light makes has tangent

tanΘ = x/18

Taking the derivative with respect to time

sec²Θ dΘ/dt = 1/18 dx/dt.

He's walking at a rate of 18 ft/sec, so dx/dt = 18.

After 3seconds,

Speed = distance/time

18ft/sec =distance/3secs

x = 18 ft/sec (3 sec)

= 54ft. At this moment

tanΘ = 54/18

= 3

sec²Θ = 1 + tan²Θ

1 + 3² = 1+9

= 10

So at this moment

10 dΘ/dt = (1/18ft) 18 ft/sec = 1

10dΘ/dt = 1

dΘ/dt = 1/10 per sec

8 0
3 years ago
A hiker in Africa discovers a skull that contains 63% of its original amount of C-14.
tester [92]

Answer:

3820 years

Step-by-step explanation:

The age of the skull can be found using carbon-14 by applying the half-life relationship.

Age of skull is given by;

t=(\frac{In\frac{N}{N0} }{-0.693} )*5730

where N=63 N₀=100 -0.693=decay factor of carbon and 5730 =half-life of carbon-14, t =age

substitute values in equation

t=(\frac{In\frac{63}{100} }{-0.693} )*5730\\\\\\t=(\frac{In0.63}{-0.693} )*5730\\\\\\t=(\frac{ -0.4620}{-0.693} )*5730\\\\\\t=(0.6667)*5730\\\\\\t=3820.29\\\\\\t=3820years

4 0
4 years ago
Please i need help
White raven [17]
Answer
I think 10
Hope this help
7 0
3 years ago
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