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4 years ago

Someone please help me! This confuses me!!

Mathematics

1 answer:

Maksim231197 [3]4 years ago

4 0

X^3 - 5 = -32

x^3 = -32 + 5

x^3 = -27

Now -27 = (-3)^3 so the answer is x = -3

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Describe or show two ways to find the following product: 1 1/3x 2.

Alenkasestr [34]

1 and 1/3 time 2? i thinks that's what you want?

or is it 1/3x squared?

I;ll presume its 1 and 1/3 time 2

first way:

Multiple whole numbers first 1 x 2 = 2

Multiple fraction by the two 1/3 x 2 = 2/3

now add them together

2 and 2/3

second way

Make 1 and 1/3 improper = 4/3

make 2 into a a/b form = 2/1

now 4/3 x 2/1 = 8/3 now make a mixed number 2 and 2/3

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A: Complementary

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Suppose μ1 and μ2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of bra

Stella [2.4K]

Answer:

The 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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$\bar X_1 =114.1$ represent the sample mean 1

$\bar X_2 =129.9$ represent the sample mean 2

n1=5 represent the sample 1 size

n2=2 represent the sample 2 size

$s_1 =5.08$ sample standard deviation for sample 1

$s_2 =5.37$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =114.1-129.9=-15.8$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_1 +n_2 -1=5+5-2=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=\pm 2.31$