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2 years ago

Someone please help me! This confuses me!!

Mathematics

1 answer:

Maksim231197 [3]2 years ago

4 0

X^3 - 5 = -32

x^3 = -32 + 5

x^3 = -27

Now -27 = (-3)^3 so the answer is x = -3

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Write the equation of a line perpendicular to 5x – 4y = - 3 that passes through the point (-5,2).

kolezko [41]

Answer: 5y + 4x = - 10

Step-by-step explanation:

Two lines are said to be perpendicular if the product of their gradients = -1.

If the gradient of the first line is $m_{1}$ and the gradient of the second line is $m_{2}$ , if the lines are perpendicular, them

$m_{1}$ x $m_{2}$ = -1 , that is

$m_{1}$ = $\frac{-1}{m_{2} }$

The equation of the line given is 5x - 4y = -3 , we need to write this equation in slope - intercept form in order to find the slope.

The equation in slope -intercept form is given as :

y =mx + c , where m is the slope and c is the y - intercept.

Writing the equation in this form , we have

5x - 4y = + 3

4y = 5x -+3

y = 5x/4 + 3/4

comparing with the equation y = mx + c , then $m_{1}$ = 5/4

Which means that $m_{2}$ = -4/5 and the line passes through the point ( -5 , 2 ).

Using the equation of line in slope - point form to find the equation of the line;

y - $y_{1}$ = m ( x - $y_{1}$ )

y - 2 = -4/5 ( x +5)

5(y - 2 ) = -4 ( x + 5 )

5y - 10 = -4x - 20

5y + 4x = - 10

4 0

2 years ago

Please help me with this

pogonyaev

ANSWER
x= 46

EXPLANATION
To solve this problem you need to remember that a straight line is 180°. This figure is basically a straight line split in two, so 134°+x=180°. You can also subtract 134 from 180 to get 46.

4 0

2 years ago

The vertex of a parabola will never be on the axis of symmetry.<br> true or false

Gala2k [10]

False, it's always on the vertex of the parabola.

4 0

2 years ago

What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!

ipn [44]

Answer:

$x = 1 + \sqrt5, x = 1 - \sqrt5$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: $ax^2 + bx + c = 0$

Quadratic Formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our Equation: $g(x) = x^2 - 2x - 4$

a = 1
b = -2
c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}$
$x = \frac{2\pm\sqrt{4 +16}}{2}$
$x = \frac{2\pm\sqrt{20}}{2}$
$x = \frac{2\pm\sqrt{4 * 5}}{2}$
$x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}$
$x = \frac{2\pm2\sqrt5}{2}$
$x = 1 + \sqrt5, x = 1 - \sqrt5$

7 0

1 year ago

HELP PLEASE IM STUCK

Anarel [89]

Answer:

y°= 51.30°

Step-by-step explanation:

Apply the formula for tangent of an angle

Tan Ф = opposite side length/adjacent side length

Tan y= 10/8

Tan y= 1.25

y° = tan⁻(1.25) = 51.34°

To the nearest tenth y°= 51.30°

8 0

2 years ago