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3 years ago

Solve the quadratic equation m2+ 2m - 24 = 0 by factoring.

Mathematics

1 answer:

12345 [234]3 years ago

7 0

Sorry , idk .........................

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Question Help

lorasvet [3.4K]

Answer:

The speed of the boat is 20 km/hr

Step-by-step explanation:

Let s be the speed of boat in still water

Let d be the distance

Upstream speed = s-4

Jane took 30 min to drive her boat upstream to water-ski at her favorite spot.

So, Distance traveled in upstream = $Speed \times time =(s-4) \times \frac{30}{60}$

Downstream speed = s+4

So, Distance traveled in downstream = $Speed \times time =(s+4) \times \frac{20}{60}$

So, $(s-4) \times \frac{30}{60}=(s+4) \times \frac{20}{60}$

30s-120=20s+80

10s=200

s=20

Hence The speed of the boat is 20 km/hr

6 0

3 years ago

A piece of wood is 1.75 meter long A carpenter saws off 0.8 meter from it. Then he saws the remaining piece into 2 pieces of equ

riadik2000 [5.3K]

1.75-0.8= 0.95m
0.95/2. to get equal halves would be 0.475m just under half a meter

5 0

3 years ago

Helllllllpppppp me plz

Genrish500 [490]

Answer:

90 degrees

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLZ HELP ASAP. (25 points)

Otrada [13]

Stretched vertically three times because you take the result of x^2+4x+4 aka (x+2)^2 and then multiply it by 3 for 3 times the output

7 0

3 years ago

Pls help asap whats the local min value of the function below?

shutvik [7]

Answer:

given function has 2 minimums - $\frac{9}{4}$ and $\frac{9}{4}$

Step-by-step explanation:

Step 1. g'(x) = 4x³ - 10x

Step 2. Find find the critical points:

4x³ - 10x = 2x(2x² - 5) = 0

$x_{1}$ = - $\sqrt{\frac{5}{2} }$ , $x_{2}$ = 0 , $x_{3}$ = $\sqrt{\frac{5}{2} }$

Step 3. g'(x) > 0 : - $\sqrt{\frac{5}{2} }$ < x < 0 or x > $\sqrt{\frac{5}{2} }$

g'(x) < 0 : x < - $\sqrt{\frac{5}{2} }$ or 0 < x < $\sqrt{\frac{5}{2} }$

Step 4.

If x ∈ ( - ∞ , - $\sqrt{\frac{5}{2} }$ ) , g(x) is decreasing ;

If x = - $\sqrt{\frac{5}{2} }$ , g(x) has minimum value ;

If x ∈ ( - $\sqrt{\frac{5}{2} }$ , 0 ) , g(x) is increasing ;

If x = 0 , g(x) has maximum value ;

If x ∈ ( 0 , $\sqrt{\frac{5}{2} }$ ) , g(x) is decreasing ;

If x = $\sqrt{\frac{5}{2} }$ , g(x) has minimum value ;

If x ∈ ( $\sqrt{\frac{5}{2} }$ , ∞ ) , g(x) is increasing .

⇒ at ( - $\sqrt{\frac{5}{2} }$ , - $\frac{9}{4}$ ) and at ( $\sqrt{\frac{5}{2} }$ , $\frac{9}{4}$ ) , g(x) reaches its minimum

8 0

3 years ago