What do you need help with hun
Answer:
red will be the bottom layer
Explanation:
in order to find its density you have to do mass/volume.
Blue: 12/3 = 3
Clear: 10/5= 2
Red: 15/3= 5
Yellow: 18/9 = 2
The one with the greates valua aka greatest density will be at the bottom layer/
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
It's A it's firm of land that's dange5
Answer: 25 of the chicks will be black
Explanation: Since the chickens are intermediate in colour, that is they are not black, they are heterozygous. Let B represent the allele for black colour and B represent the allele for blue colour, therefore the genotype of a chicken with an intermediate colour is Bb. A cross between two Bb chicken will produce 1 BB, 2 Bb and 1 bb chicks. 1 BB will manifest outwardly as black, 2Bb will manifest outwardly as intermediate colored while 1 bb will manifest outwardly as blue colored chicks.
Since one out of four chicks are black colored, if the two chicken produced 100 chicks, the number of chicks that will be black is 1/4 x 100 = 25. Therefore, 25 chicks out of 100 will be black.
See the attached punnet square for more information
