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Nutka1998 [239]
3 years ago
7

I need help solving this please

Mathematics
1 answer:
lina2011 [118]3 years ago
6 0
Idk ask another person sorrt
You might be interested in
NEED HELP HERE ASAP<br><br> 6. Find the cube roots of 27(cos 330° + i sin 330°).
VLD [36.1K]
<span>we have that

the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

 cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
7 0
3 years ago
Helpppppppppppppppp it is due now
Fudgin [204]

Hey mate hope its help you...

5 0
3 years ago
Read 2 more answers
Can someone please help
kicyunya [14]

Answer:

hardd  sorry

Step-by-step explanation:>..

7 0
3 years ago
What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?
anyanavicka [17]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f( - 4) = 4( - 4) + 9 =  - 7

_________________________________

f( - 2) = 4( - 2) + 9 = 1

_________________________________

f(0) = 4(0) + 9 = 9

_________________________________

f(2) = 4(2) + 9 = 17

_________________________________

Thus ;

R = { - 7 , 1 , 9 , 17 }

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is (( D )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 0
2 years ago
Kevin is observing the population of the fish he put into a pond. He built a pond and populated it with 500 fish. The population
laila [671]

Here we will use exponential form, which is

y = y_{0} e^{kt}

Initial value, y0 = 500

Double of 500 = 1000

1000 = 500e^{k*1}

2 = e^k

k= ln (2)

Required equation is

y=500e^{x ln2} \\ y= 500 (2)^x

6 0
3 years ago
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