Answer:
x ≈ 1318.2
Step-by-step explanation:
<em>Tangent = opposite over adjacent</em>
<em />![tan^{-1}[tan(\frac{x}{15})] = tan^{-1}(27)](https://tex.z-dn.net/?f=tan%5E%7B-1%7D%5Btan%28%5Cfrac%7Bx%7D%7B15%7D%29%5D%20%3D%20tan%5E%7B-1%7D%2827%29)
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<em />![x = 15[tan^{-1}(27)]](https://tex.z-dn.net/?f=x%20%3D%2015%5Btan%5E%7B-1%7D%2827%29%5D)
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x ≈ 1318.2
Answer:
the remaining mass of unobtanium -41 after a 5 seconds, 10 seconds, 15 seconds and 20 seconds is 24 gr, 12 gr , 5.33 gr and 3 gr respectively
Step-by-step explanation:
the equation that governs the remaining mass m of unobtanium -41 after a time t is
m=m₀*2^(-t/T) , where t is in seconds ,m₀ represents initial mass and T=half-life
Therefore
a) for t=5 s
m=48 gr*2^(-t/5 s) = 48 gr*2^(-5 s/5 s) = 48 gr/2 = 24 gr
b) for t=10 s
m=48 gr*2^(-t/5 s) = 48 gr*2^(-10 s/5 s) = 48 gr/4 = 12 gr
b) for t=15 s
m=48 gr*2^(-t/5 s) = 48 gr*2^(-15 s/5 s) = 48 gr/9 = 5.33 gr
b) for t=20 s
m=48 gr*2^(-t/5 s) = 48 gr*2^(-20 s/5 s) = 48 gr/16 = 3 gr
thus the remaining mass of unobtanium -41 after a 5 seconds, 10 seconds, 15 seconds and 20 seconds is 24 gr, 12 gr , 5.33 gr and 3 gr respectively
Answer:
Step-by-step explanation:
