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3 years ago

How do I find side length x and would I use sin cos or tan

Mathematics

1 answer:

kifflom [539]3 years ago

3 0

Check the picture below.

Make sure your calculator is in Degree mode.

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6 2/3 divided by 2 thank you please help me answer this

AURORKA [14]

Answer:

should be 3, or try 3.3 OR 3.33333

6 0

3 years ago

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Please help, much appreciated, will give brainliest :)

DIA [1.3K]

Answer:

so if you multiple4.8 percent by 3,000 u get 144 and then u divide by 3 and that u u 48 dollars per year

7 0

3 years ago

The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?

Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are $(x_{1}, y_1)$ and $(x_2, y_2)$ then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

$(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})$

Thus for our question the endpoints are $(x_E, y_E)$ and $(x_F, y_F)$ and hence the midpoint will be:

$(x_M, y_M)=$ $(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})$

Thus, Option C is the correct option.

6 0

3 years ago

ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports

iVinArrow [24]

Answer:

He have 15 action games and 24 sports games.

Step-by-step explanation:

Given:

Ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports collection.

Now, to find the number of action games and sports games.

Let the sports games be $x.$

As, given his action collection is three more than half his sports collection.

Thus, the action games = $3+\frac{x}{2}$ .

Total number of video games = 39.

So, we set an equation to get the number of action games and sports games:

$x+(3+\frac{x}{2})=39$

$x+3+\frac{x}{2} =39$

Subtracting both sides by 3 we get:

$x+\frac{x}{2} =36$

$\frac{2x+x}{2}=36$

$\frac{3x}{2} =36$

Multiplying both sides by 2 we get:

$3x=72$

Dividing both sides by 3 we get:

$x=24.$

The sports games he have = 24.

Now, to get the action games we substitute the value of $x$ :

$3+\frac{x}{2}$

= $3+\frac{24}{2}$

= $3+12$

= $15.$

The action games he have = 15.

Therefore, he have 15 action games and 24 sports games.

6 0

3 years ago

What is 53/200 as a percent.

taurus [48]

$\frac { 53 }{ 200 } \\ \\ =\frac { 26.5 }{ 100 } \cdot \frac { 2 }{ 2 } \\ \\ =\frac { 26.5 }{ 100 } \cdot 1\\ \\ =\frac { 26.5 }{ 100 }$

Therefore your answer is 26.5%.

4 0

3 years ago

Read 2 more answers