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Vadim26 [7]
3 years ago
14

Question 1

Mathematics
1 answer:
8090 [49]3 years ago
4 0

Question 1- A

Question 2- C

Question 3- B

Question 4- C

Question 5- A

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aleksklad [387]
211,135.71 merry christmas
5 0
2 years ago
This should be easy for you <br> Please help me
Alik [6]

Explanation:

a. The line joining the midpoints of the parallel bases is perpendicular to both of them. It is the line of symmetry for the trapezoid. This means the angles and sides on one side of that line of symmetry are congruent to the corresponding angles and sides on the other side of the line. The diagonals are the same length.

__

b. We observe that adjacent pairs of points have the same x-coordinate, so are on vertical lines, which have undefined slope. KN is a segment of the line x=1; LM is a segment of the line x=3. If the trapezoid is isosceles, the midpoints of these segments will be on a horizontal line. The midpoint of KN is at y=(3-2)/2 = 1/2. The midpoint of LM is at y=(1+0)/2 = 1/2. These points are on the same horizontal line, so the trapezoid <em>is isosceles</em>.

__

c. We observed in part (b) that the parallel sides are KN and LM. The coordinate difference between K and L is (1, 3) -(3, 1) = (-2, 2). That is, segment KL is the hypotenuse of an isosceles right triangle with side lengths 2, so the lengths of KL and MN are both 2√2.

_____

For part (c), we used the shortcut that the hypotenuse of an isosceles right triangle is √2 times the leg length.

7 0
3 years ago
Factor the trigonometric equation.<br> cos2x-cosx
prisoha [69]

Cos(2x) = cos^2(x) - sin^2(x) - cos(x)

but sin^2(x) = 1 - cos^2(x)

cos(2x) - cos(x) = cos^2(x) - (1 - cos^2(x) ) - cos(x)

cos(2x) - cos(x) = cos^2(x) - 1 + cos^2(x) - cos(x)

cos(2x) - cos(x) = 2cos^2(x) - 1 - cos(x)

cos(2x) - cos(x) = (2cos(x) + 1)(cos(x) - 1)

I think this is what you have asked for.

4 0
3 years ago
Which expression is equivalent to<br> (X^1/4 y^16)^1/2?
lawyer [7]

Answer:

x^{\frac{1}{8} } y^{8}

Step-by-step explanation:

Given :

(x^\frac{1}{4}  y^{16} )^{1/2}

Now,

(x^\frac{1}{4}  y^{16} )^{1/2}\\x^{\frac{1}{8} } y^{8}

Therefore, expression is equivalent to x^{\frac{1}{8} } y^{8}

3 0
3 years ago
The vertex of the parabola is at the point (2,-5). which of the equations below could be the one for this parabola?
timofeeve [1]
Hello,
Answer is Dsince y=k(x-2)²-5  and if k=1 ==>D.

7 0
3 years ago
Read 2 more answers
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