Answer:
Step-by-step explanation:
∠D ≅ ∠R
DC ≅ RK
So, If ∠C ≅ ∠K,
Then ΔDCS ≅ ΔRKO by Angle Side Angle congruent. {A S A}
OR
DC ≅ RK
∠D ≅ ∠R
If SD ≅ OR , then
ΔDCS ≅ ΔRKO by Side Angle Side congruent {S A S}
Full Question:
Find the volume of the sphere. Either enter an exact answer in terms of π or use 3.14 for π and round your final answer to the nearest hundredth. with a radius of 10 cm
Answer:
The volume of the sphere is ⅓(4,000π) cm³ or 4186.67cm³
Step-by-step explanation:
Given
Solid Shape: Sphere
Radius = 10 cm
Required
Find the volume of the sphere
To calculate the volume of a sphere, the following formula is used.
V = ⅓(4πr³)
Where V represents the volume and r represents the radius of the sphere.
Given that r = 10cm,.all we need to do is substitute the value of r in the above formula.
V = ⅓(4πr³) becomes
V = ⅓(4π * 10³)
V = ⅓(4π * 10 * 10 * 10)
V = ⅓(4π * 1,000)
V = ⅓(4,000π)
The above is the value of volume of the sphere in terms of π.
Solving further to get the exact value of volume.
We have to substitute 3.14 for π.
This gives us
V = ⅓(4,000 * 3.14)
V = ⅓(12,560)
V = 4186.666667
V = 4186.67 ---- Approximated
Hence, the volume of the sphere is ⅓(4,000π) cm³ or 4186.67cm³
Answer:
(x, y) ⇒ (-x√3/2 +y/2, -x/2 -y√3/2)
Step-by-step explanation:
The rule for CCW rotation through an angle α is ...
(x, y) ⇒ (x·cos(α) -y·sin(α), x·sin(α) +y·cos(α))
So, for α = 210°, the rule becomes ...
(x, y) ⇒ (-x√3/2 +y/2, -x/2 -y√3/2)
