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3 years ago

Point B is on a line that has a slope of 2. Which of these could be the coordinates of another point on the line?

Mathematics

2 answers:

zmey [24]3 years ago

7 0

the answer is (1,2)

8_murik_8 [283]3 years ago

5 0

Slope = rise over run.

When slope = 2:

rise = 2
run = 1

Point B is at (2,4)

To get your answer, your equation will look like: (x + 1, y + 2)

Plug in 2 for x, and 4 for y

(2 + 1, 4 + 2) = (3,6)

Simplify. divide 3 from both x and y

3/3 = 1
6/3 = 2

(1.2) is your other point, and is your answer

hope this helps

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Step-by-step explanation:

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3 years ago

Select ALL the correct answers.<br> Select all functions that have a y-intercept of (0,5).

otez555 [7]

1.) f(x)=7(b)^x-2
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2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No

3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No

4.) f(x)=-5(b)^x+10
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5.) f(x)=2(b)^x+5
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Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10

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3 years ago

Explain why f(x) = x2+4/x2-x-2 is not continuous at x = 2.

xxTIMURxx [149]

Answer: Option a.

Step-by-step explanation:

Make the denominator equal to zero and solve for x:

Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:

$x^{2}-x-2=0\\(x-2)(x+1)=0\\x=2\\x=-1$

Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2

The answer is the option a.

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3 years ago

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