Answer:
2.25
Step-by-step explanation:
The computation of the number c that satisfied is shown below:
Given that
Interval = (0,9)
According to the Rolle's mean value theorem,
If f(x) is continuous in {a,b) and it is distinct also
And, f(a) ≠ f(b) so its existance should be at least one value
i.e
After this,
After this,
Put the values of a and b to the above equation
![f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}](https://tex.z-dn.net/?f=f%5Ei%28c%29%20%3D%20%5Cfrac%7Bf%28b%29%20-%20f%28a%29%7D%7Bb%20-%20a%7D%20%20%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B%7B2%7D%5Csqrt%7Bc%7D%20%7D%20%3D%20%5Cfrac%7B3%20-0%7D%7B9-0%7D%20%20%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B%5Csqrt%5B2%5D%7Bc%7D%20%7D%20%3D%20%5Cfrac%7B3%7D%7B9%7D%20%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B%5Csqrt%5B2%5D%7Bc%7D%20%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5C%5C%5C%5C%20%5Csqrt%5B2%5D%7Bc%7D%20%3D%203%5C%5C%5C%5C%5Csqrt%7Bc%7D%20%3D%20%5Cfrac%7B3%7D%7B2%7D%20%5C%5C%5C%5C%20c%20%3D%20%5Cfrac%7B9%7D%7B4%7D)
= 2.25
Answer:
Option B - 35.4 VAC
Step-by-step explanation:
Formula for peak voltage is;
V_p = V_rms × √2
Making V_rms the formula, we have;
V_rms = (V_p)/√2
We are given:Peak voltage: V_p = 50 VAC
Where 50 VAC means 50 Volts AC power
Thus;
V_rms = 50/√2
V_rms ≈ 35.4 VAC
So option B is correct
Answer:Same
Step-by-step explanation:just flip the up side down one.
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
The average rate of change of the function at the interval is -8
<h3>How to determine the average rate of change?</h3>
The table that completes the question is added as an attachment
From the table, we have:
f(5) = -26
f(3) = -10
The average rate is then calculated as:
Rate = (f(5) - f(3))/(5 -3)
This gives
Rate = (-26 + 10)/(5 -3)
Evaluate
Rate = -8
Hence, the average rate of change of the function is -8
Read more about average rate of change at:
brainly.com/question/8728504
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