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skad [1K]
3 years ago
7

a coach bought three soccer balls on sale. they normally sell for $26 each. they were on sale for $7 off the original price. the

total tax on the ball was $4 . the expression represents the total amount paid. Then explain how to use the order of operations to find the total amount the coach paid for the soccer balls.
Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0

Answer:

The coach paid $69 on the three soccer balls

Step-by-step explanation:

If the coach bought 3 soccer balls for 26$, minus the $7 on each, plus the $4 tax on each, the expression would be:

3 × (26 - 7 + 4)

We put the addition and subtraction in parentheses because of PEMDAS. PEMDAS say we must solve for whatever is in the parentheses first, then exponents (there are none in the expression), ans then multiplication. If those numbers were not in parentheses, the answer would look completely different as we would multiply before subtracting and adding. We must find the total amount each ball cost first:

26 - 7 + 4 = 23

Each ball cost $23

If the coach bought 3 balls for $23 each, we have to multiply the two numbers:

3 × $23

$69

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(y1-y2)/(x1-x2)

(x,y)
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4. Use the process outlined in the lesson to approximate the number 2√3. Use the approximation √3 ≈ 1.732 050 8.
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Answer:

sequence of five intervals

(1) 2  < 2^{\sqrt{3} }   < 2^{2}

(2) 2^{1.7}  < 2^{\sqrt{3} }    < 2^{1.8}

(3) 2^{1.73}  < 2^{\sqrt{3} }    < 2^{1.74}

(4) 2^{1.732}  < 2^{\sqrt{3} }    < 2^{1.733}

(5) 2^{1.7320}  < 2^{\sqrt{3} }    < 2^{1.7321}

Step-by-step explanation:

as per question given data      

√3 ≈ 1.732 050 8 

to find out      

sequence of five intervals

solution      

as we have given that √3 value that is here

√3 ≈ 1.732 050 8            ........................1

so  

when we find 2^{\sqrt{3} }           ................2

put here √3 value in equation number  2  

we get  2^{\sqrt{3} }   that is  3.322    

so    

sequence of five intervals

(1) 2  < 2^{\sqrt{3} }   < 2^{2}

(2) 2^{1.7}  < 2^{\sqrt{3} }    < 2^{1.8}

(3) 2^{1.73}  < 2^{\sqrt{3} }    < 2^{1.74}

(4) 2^{1.732}  < 2^{\sqrt{3} }    < 2^{1.733}

(5) 2^{1.7320}  < 2^{\sqrt{3} }    < 2^{1.7321}

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7
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