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Maslowich
3 years ago
10

a helicopter is flying at 150mph on a course with a bearing of 130°. If the helicopter experiences a crosswind blowing southeast

at 25 mph, find the resultant speed and direction of the helicopter.​
Mathematics
1 answer:
romanna [79]3 years ago
3 0

150-25=125mph

130-25=105

This means it was going 125mph and that it dropped an altitude of 25 degrees because of the wind and the slow down of the helicopter

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SIZIF [17.4K]
X=4
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4 0
3 years ago
Using identity evaluate: (104)²​
SOVA2 [1]

Answer:

104×104=10816

Step-by-step explanation:

104²=104×104

=10816

8 0
2 years ago
Can someone help me with number 8?
Hoochie [10]

Answer:

Step-by-step explanation:

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6 0
2 years ago
I'd greatly appreciate the help-
dem82 [27]

Answer:

The 3rd option

Step-by-step explanation:

To prove that 2 triangles are similar, we need to prove that 2 pairs of their angle measurements are congruent.

This is because all triangles have 180 degrees, so if 2 pairs are congruent, the remaining angles will also be congruent

We know that m<D=m<E

We also know that m<DCA=m<ECB because they are vertical angles.

Vertical angles are always congruent.

Therefore, the triangles are similar.

The correct similarity statement would be 1, since <D corresponds with <E.

Now let's look at the 3rd Statement. To prove that two lines are similar, we would have to prove that their alternate interior angles are congruent.

A pair of alternate interior angles would be <D and B or or <E  and <A

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7 0
3 years ago
Please help me with this
Zolol [24]

Answer:

294.5 m²

Step-by-step explanation:

shaded region = area of major sector + area of triangle

central angle of major sector = 360° - 130° = 230°

area of sector = area of circle × fraction of circle

A = π × 11.1² × \frac{230}{360}

   = \frac{x11.1^2(230)\pi }{360} ≈ 247.3 m²

area of triangle = 0.5 × 11.1 × 11.1 × sin130° ≈ 47.2 m²

shaded area = 247.3 + 47.2 ≈ 294.5 m²

7 0
3 years ago
Read 2 more answers
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