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LenaWriter [7]
2 years ago
11

4/1 sqrt3-sqrt2 rationalize?

Mathematics
1 answer:
Triss [41]2 years ago
8 0
\dfrac{4}{\sqrt3-\sqrt2}=\dfrac{4}{\sqrt3-\sqrt2}\cdot\dfrac{\sqrt3+\sqrt2}{\sqrt3+\sqrt2}=\dfrac{4(\sqrt3+\sqrt2)}{(\sqrt3)^2-(\sqrt2)^2}\\\\=\dfrac{4\sqrt3+4\sqrt2}{3-2}=4\sqrt3+4\sqrt2
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