Answer:
Michael
Step-by-step explanation:
Look at the table below:
The probability of selecting a sale that was made by Quentin is .30, by Michael is .45 and by Bubba is .25.
Since Quentin completes paperwork 90% of the time, he doesn't complete paperwork 10% of the time, following this reasoning we can say that Michael doesn't complete paperwork 20% of the time and Bubba doesn't complete paperwork 15% of the time.
The probability of selecting a file and that it belongs to Quentin AND is incomplete is:
(Probability of selecting a Quentin's file) x (Probability is a Quentin incomplete file) = (0.30)(0.10) = 0.03
Using this same method we have that the probability that it belongs to Michael and is incomplete is (.45)(.20) = 0.09
That it belongs to Bubba and it's incomplete is (0.25)(0.15) = 0.037
The highest of these probabilities is the one that corresponds to Michael: 0.09, therefore he is the most likely culprit.
Answer:
5<3
Step-by-step explanation:
8-3= 5
Answer:
x=<u>1</u>
2
hope it helps
Step-by-step explanation:
–1
x=0.5,x=2
N(t)= 15000 e^(.07 t)
let's assume 2005 is 0 and 2013 will be 8 years.
n(8)=15000e^(.07*8) = 26260 growth of foxes.
Answer:
2695.04348
Well, I don't want to do ALL of the work but I'll give you an idea of how I got it:
First, ask yourself, "How many times does 23 go into 61?" which is the same thing as 61 divided by 23.
23 times 2 equals 46. I chose this number because 23 times 3 equals 69 and that is too much.
(The first digit is 2)
So 61 minus 46 equals 15. Then you bring down the 9 and divide 159 by 23.
23 times 6 is 138 and the closest you will get. Again, 159 minus 138 equals 21.
(Now the second digit of the answer is 6)
Bring down the 8 to get 218. 218 divided by 23 equals 9 (well, not exactly, but you get what I mean). 23 times 9 equals 207. 218 minus 207 equals 11.
(Don't forget, the third digit in the answer is now 9)
Keep doing this until you get your final answer, which I already gave you at the top to double check. When you reach the last number of 61,986 (which is 6), go into the decimal place and keep on working from there.