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2 years ago

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Boat A and Boat B are racing across a bay. Boat A is 6 miles ahead of Boat B. Boat A has a top speed of 36 miles per hour, but B

oat B has a top speed of 44 miles per hour.

1 answer:

Finger [1]2 years ago

4 0

Answer:

idk1234

Step-by-step explanation:

idk idk idk idk13579-=

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Given: F(x) = 2x - 1; G(x) = 3x + 2; H(x) = x 2<br><br> Find F{G[H(2)]}

Tamiku [17]

H(2)=x²=2²=4
G[H(2)]=G(4)=3(4)+2=12+2=14
F[G[H(2)]]=F(14)=2(14)-1=28-1=27

Answer: F[G[H(2)]]=27

4 0

3 years ago

Read 2 more answers

Use the functions and the scenario to solve the problem.

Naily [24]

Answer:

Leanne is correct. It is important that g(x) is subtracted from f(x).

Shiloh is incorrect. She subtracted f(x) from g(x), and subtraction isn't commutative.

*Just took the test, got the answer correct!! Hope this helps!

7 0

2 years ago

If 20% of the people in a community use the emergency room at a hospital in one year, find

Pie

Answer:

a) 87.91% probability that at most three used the emergency room

b) 20.13% probability that exactly three used the emergency room.

c) 3.28% probability that at least five used the emergency room

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they use the emergency room, or they do not. The probability of a person using the emergency room is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Sample of 10 people:

This means that $n = 10$

20% of the people in a community use the emergency room at a hospital in one year

This means that $p = 0.2$

a) At most three used the emergency room

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074$

$P(X = 1) = C_{10,1}.(0.2)^{1}.(0.8)^{9} = 0.2684$

$P(X = 2) = C_{10,2}.(0.2)^{2}.(0.8)^{8} = 0.3020$

$P(X = 3) = C_{10,3}.(0.2)^{3}.(0.8)^{7} = 0.2013$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1074 + 0.2684 + 0.3020 + 0.2013 = 0.8791$

87.91% probability that at most three used the emergency room

b) Exactly three used the emergency room

$P(X = 3) = C_{10,3}.(0.2)^{3}.(0.8)^{7} = 0.2013$

20.13% probability that exactly three used the emergency room.

c) At least five used the emergency room

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

From 0 to 3, we already have in a).

$P(X = 4) = C_{10,4}.(0.2)^{4}.(0.8)^{6} = 0.0881$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.1074 + 0.2684 + 0.3020 + 0.2013 + 0.0881 = 0.9672$

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.9672 = 0.0328$

3.28% probability that at least five used the emergency room

4 0

3 years ago

In a survey of 300 voters, 68 said that they voted for Candidate A. How many voters can Candidate A expect to receive if the pop

Zepler [3.9K]

If you meant 1,000 then there would be 227 voters Candidate A can expect to receive.
If you meant 10,000 then there would be 2267 voters Candidate A can expect to receive.

3 0

3 years ago

Find the largest number which divides 870 and 260 leaving the remainders 3 and 5 respectively

stira [4]

Answer:

51

Step-by-step explanation:

You first subtract 3 from 870 and 5 from 260.Then you find the greatest common divisor of 255 and 867.

5 0

3 years ago