The answer is the 4th option,
x+y=6 and x-y= -10
I believe the answer is ten pairs...
The two rows each have 3 pairs touching, and the four columns each have 1, which makes 2*3 + 4*1 = 10
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
This is more of a computer kind of thing, but try clicking the next thing at the bottom.
Step-by-step explanation:
48 divided by 6= 8
8 x 4 = 32
She can bake 32 cakes