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Vika [28.1K]
3 years ago
14

Sung Lee invests $3,000 at age 18. He hopes the investment will be worth $6,000 when he turns 25. If the interest compounds cont

inuously, approximately what rate of growth will he need to achieve his goal? Round to the nearest tenth of a percent.
Mathematics
1 answer:
il63 [147K]3 years ago
7 0

Answer:

10.4%

Step-by-step explanation:

Sung Lee invests $3,000 at age 18.

He hopes the investment will be worth $6,000 when he turns 25, that is, after 7 years.

The interest compounds (Compound Interest). The formula for the final amount in a compound interest is:

A = P(1 + R)^T

where P = Principal (Amount invested) = $3000

A = final amount = $6000

R = rate

T = number of years = 7 years

This implies that:

6000 = 3000(1 + R)^7\\\\\frac{6000}{3000} = (1 +R)^7\\\\2 = (1 + R)^7

Find the 7th root of 2:

\sqrt[7]{2} = (1 + R)\\\\1.104 = (1 + R)\\\\=> R = 1.104 - 1\\\\R = 0.104

=> R = 10.4%

Hence, the rate would need to be 10.4% for him to achieve his goal.

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8 4/5 - 2/3 - ? = 3 1/10​
Dimas [21]

Answer: 5 1/30

Step-by-step explanation:

8 + 4/5 - 2/3 - 3 - 1/10 = 5 + 1/30

5 0
2 years ago
The radius of a circle is 3.9 in. Find the circumference to the nearest tenth.
masha68 [24]

Answer:

C = 24.5 in

Step-by-step explanation:

Formula to find the circumference of a circle is :

C = 2πr

Here,

r ⇒ radius

So let us solve now.

C = 2πr

C = 2 × π × r

C = 2 × 3.14 × 3.9

C = 24.492 in

So, they've asked for nearest 10th.

Therefore, the answer will be 24.5 in.

Hope this helps you :-)

Let me know if you have any other questions :-)

8 0
3 years ago
Read 2 more answers
Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...
Strike441 [17]

Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

\displaystle -3x -1, \, 4x +4, \, 11x  + 9 \dots

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}

Find the common difference by subtracting the first term from the second:

d = (4x+4) - (-3x - 1)

Distribute:

d = (4x + 4) + (3x + 1)

Combine like terms. Hence:

d = 7x + 5

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

\displaystyle x_n = a + d(n-1)

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)

To find the 13th term, let <em>n</em> = 13. Hence:

\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)

Simplify:

\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}

The 13th term is 81<em>x</em> + 59.

3 0
3 years ago
Which of the following demonstrates how the 20 is calculated using the<br> combination pattern?
ZanzabumX [31]

Answer:

D

Step-by-step explanation:

The diagram shows Pascal's triangle. Pascal's triangle is a triangular array of the binomial coefficients.

The entry in the n^{th} row (start counting rows from 0) and k^{th} column (start counting columns from 0) of Pascal's triangle is denoted by

C^n_k=\left(\begin{array}{c}n\\ k\end{array}\right)

Coefficient 20 stands in 6th row, then n = 6 and in 3rd column, so k = 3.

Hence,

20=C^6_3=\left(\begin{array}{c}6\\ 3\end{array}\right)=\dfrac{6!}{3!(6-3)!}

4 0
3 years ago
Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b
Korolek [52]
Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0



4 0
3 years ago
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